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mylen [45]
2 years ago
11

6. A 3 liter solution contains 140 g of Sodium Bromide (NaBr). What is the molarity of the solution?

Chemistry
1 answer:
Ludmilka [50]2 years ago
8 0

The molarity = 0.454 M

<h3>Further solution</h3>

Given

Volume = 3 L of solution

mass = 140 g of NaBr

Required

The molarity

Solution

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}

mol of NaBr :

= mass : MW

= 140 g : 102,894 g/mol

= 1.361

Molarity :

= 1.361 mol : 3 L

= 0.454 M

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melomori [17]

The molar mass of NaCl is 23 + 35.5 = 58.5 g/mol, so the mass of the sample ia 0.78 × 58.5 = 45.63 g.

4 0
3 years ago
A 50.6 grams sample of magnesium hydroxide (Mg(OH)2) is reacted with 45.0 grams of hydrochloric acid (HCl). What is the theoreti
zysi [14]
            <span> Mg(OH)2(s) + 2HCl(aq) yield MgCl2(aq) + 2H2O(l)

grams HCl required = (50.6 grams Mg(OH)2) * (1 mol Mg(OH)2 / 58.3197 grams Mg(OH)2) * (2 mol HCl / 1 mol Mg(OH)2) * (36.453 grams HCl / 1 mol HCl) = 63.26 grams HCl required

Since there are only 45.0 grams HCl, then HCl is the limiting reactant.

theoretical yield MgCl2 = (45.0 grams HCl) * (1 mol HCl / 36.453 grams HCl) * (1 mol MgCl2 / 2 mol HCl) * (95.211 grams MgCl2 / 1 mol MgCl2) = 58.6 grams MgCl2 </span>
7 0
3 years ago
Read 2 more answers
What is the mass of H2O produced when 14.0 grams of H2 reacts completely with 2.0 grams of O2?
Vladimir79 [104]
Balanced chemical equation:

2 H2 + 1 O2 = 2 H2O

4 g H2  -------> 32 g O2 -----------> 36 g H2O
   ↓                       ↓                             ↓
14.0 g ---------> 2.0 g O2 ----------> mass H2O ?

32 * mass H2O = 2.0 * 36

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hope this helps!.


4 0
3 years ago
What is the energy of light with a wavelength of 468 nm? (The speed of light
marshall27 [118]

The answer for the problem is explained below.

The option for the answer is "D".

<u><em>Therefore the energy of the light is  4.25 × 10^-19 J</em></u>

Explanation:

Given:

wavelength (λ) = 468 nm = 468×10^-9 m

speed of light (c) = 3.00 x 10^8m/s

Planck's constant is 6.626 x 10^-34J·s

To solve:

energy of light (E)

We know,

E =(h×c) ÷ λ

E = ( 6.626 x 10^-34 ×  3.00 x 10^8) ÷ 468×10^-9

E = 4.25 × 10^-19 J

<u><em>Therefore the energy of the light is  4.25 × 10^-19 J</em></u>

6 0
3 years ago
Now they feel it is best to have you identify an unknown gas based on its properties. Suppose 0.508 g of a gas occupies a volume
pishuonlain [190]

Answer: Option (b) is the correct answer.

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Hence, putting all the given values into the ideal gas equation as follows.

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As the molar mass of a chlorine atom is 35.4 g/mol and it exists as a gas. So, molar mass of Cl_{2} is 70.8 g/mol or 71 g/mol (approx).

Thus, we can conclude that the gas is most likely chlorine.

4 0
3 years ago
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