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3 years ago

What's is the question for this problem

Mathematics

1 answer:

rodikova [14]3 years ago

7 0

all the no s ok but if you don't get it right

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for every 4 miles Vanessa jogged, Cody jogged 3 miles. if Vanessa jogged 1 mile, how far would Cody have jogged

Ksju [112]

Alright here's the breakdown:

it said every 4 miles Vanessa jogged, Cody jogged 3 miles.

so

Vanessa jogged 1 mile

that means

Cody jogged .75 of a mile ( or 75% of 1 )

because

Cody will always jog 75% of how much Vanessa joged

so say that

Vanessa jogged 50 miles

all you do is take 75% of how much Vanessa jogged

and that should be how much Cody joged

hopes this helps!

7 0

3 years ago

Read 2 more answers

How far from zero is -2.5?

ollegr [7]

Answer:2.5

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Will name brainliest please help me.

Ede4ka [16]

Answer:

CD = 9

Step-by-step explanation:

ΔADE is similar to ΔBCD

Such that:

AD is similar to CD

BD is similar to ED

AE is similar to BC

Taking the proportion of their sides to find the unknown sides CD

=> $\frac{6}{2} = \frac{CD}{3}$

Cross Multiplying

=> 2(CD) = 3*6

=> CD = 18/2

=> CD = 9

3 0

4 years ago

Two angles are given.

LUCKY_DIMON [66]

Answer:

Angle g and h are complementary angles.

Angle g and h are acute angles.

Step-by-step explanation:

The given angles are

$m\angle g=(2x-90)^{\circ}$

$m\angle h=(180-2x)^{\circ}$

If sum of two angles is 180, then they called supplementary angles.

If sum of two angles is 90, then they called complimentary angles.

Add both angles.

$m\angle g+m\angle h=(2x-90)^{\circ}+(180-2x)^{\circ}$

$m\angle g+m\angle h=(2x-90+180-2x)^{\circ}$

$m\angle g+m\angle h=90^{\circ}$

The sum of two angles is 90 degree, therefore angle g and h are complementary angles.

Both angles are greater than zero and their sum is 90, it means

$0$ and $0$

Therefore, angle g and h are acute angles.

7 0

3 years ago

Aunt Thelma planted an herb garden. She planted rosemary in 2/9 of the garden. She

Reptile [31]

Answer:

$\dfrac{17}{45}$

Step-by-step explanation:

Fraction on which Rosemary was planted $=\dfrac{2}{9}$

Fraction on which dill was planted $=\dfrac{2}{5}$

Let the fraction on which chives was planted=x

Then:

$\dfrac{2}{9}+\dfrac{2}{5}+x=1\\$Since the LCM of 9 and 5 is 45\\We multiply all through by 45\\45\left(\dfrac{2}{9}\left)+45\left(\dfrac{2}{5}\right)+45x=45(1)$\\10+18+45x=45\\45x=45-28\\45x=17\\Divide both sides by 45\\x=\dfrac{17}{45}$

The fraction of the garden on which Chives was planted is $\dfrac{17}{45}$

6 0

3 years ago

What's is the question for this problem​

What's is the question for this problem