Answer:
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Answer:
The fifth degree Taylor polynomial of g(x) is increasing around x=-1
Step-by-step explanation:
Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:
and when you do its derivative:
1) the constant term renders zero,
2) the following term (term of order 1, the linear term) renders: 
since the derivative of (x+1) is one,
3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero
Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: 
as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1
Answer:
- after the raise, her salary is $1755 per month
- this is a +17% change from her original salary
Step-by-step explanation:
The multiplier of her original salary to her reduced salary is ...
(1 - 10%) = 0.90
The multiplier of her reduced salary after her raise is ...
(1 +30%) = 1.30
The multiplier of her raised salary from her original salary is ...
(0.90)(1.30) = 1.17 = (1 +17%)
Her salary after the 17% raise is ...
1.17·1500/mo = $1755/mo
So you wanna find the area of each surface:
For the large square surface in the top you do 12*15=180 and there are two large squares faces so you multiply 180 by 2 which equals 360 then you find the small rectangle faces: 5*15=75 and multiply by 2 Bc there are 2 faces like that so it would be 75*2=150 then for the last faces you do 12*5= 60 *2= 120 at the end I add all of the faces up, 360+150+120=630
D= # of dimes
q= # of quarters
QUANTITY EQUATION:
d + q= 64
COST EQUATION:
0.10d + 0.25q= $9.25
STEP 1:
multiply quantity equation by -0.10 to be able to eliminate the d term in step 2
(-0.10)(d + q)= (-0.10)(64)
-0.10d - 0.10q= -6.40
STEP 2:
add equation from step 1 to cost equation to eliminate the d term and solve for q
Add
0.10d + 0.25q= $9.25
-0.10d - 0.10q= -6.40
0.15q= 2.85
divide both sides by 0.15
q= 19 quarters
STEP 3:
substitute q value in step 2 into either original equation to find d value
d + q= 64
d + 19= 64
subtract 19 from both sides
d= 45 dimes
CHECK:
0.10d + 0.25q= $9.25
0.10(45) + 0.25(19)= 9.25
4.50 + 4.75= 9.25
9.25= 9.25
ANSWER: There are 45 dimes and 19 quarters.
Hope this helps! :)
