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1 year ago

Evaluate the expression below when x = 4 and y = 12. 5x2−3y

Mathematics

1 answer:

Svetllana [295]1 year ago

3 0

Answer:

Step-by-step explanation:

substitute x = 4 and y = 12 into the expression

5x² - 3y

= 5(4)² - 3(12)

= 5(16) - 36

= 80 - 36

= 44

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Dan bought a truck for $29,800. The value of the truck depreciated at a constant rate per year. The table shows the value of the

leonid [27]

Answer:

A) f(t) = 29,800(0.89)^t

Step-by-step explanation:The truck value decreases by 11% each year.

The present value of the truck was $29,800.

29,800 x 0.11 = 3,728 dollars lost from value.

29,800 - 3,728 = 26,522, the value of the truck after one year.

26,522 x 0.11 = 2,917.42 cash lost from value.

26,522 - 3,728 = 23,604.58, the value of the truck after two years.

Therefore, the answer is A) f(t) = 29,800(0.89)^t.

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2 years ago

Which expression has the same value as 8 + 2(3+x)?

Effectus [21]

8 + 2(3 + x) = 8 + 6x + 2
= 6x + 10

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3 years ago

Oh, boy! Look at that monthly payment from Question 2 above! Molly cannot afford the monthly payment using the 0% financing. She

viktelen [127]

The car payment plan that has an APR of 1.9% is, on the short term, pocket

friendly.

The correct responses are;

First part: The amount of loan Molly needs is $22,495

Second part: Molly's monthly payment will be approximately $286.2

Third part: The total interest Molly will pay using the plan is approximately $1,545.8

Fourth part: The amount the car costs Molly using the plan is approximately $26,540.8

Reasons:

The question parameters are;

Molly is comparing Auto Loans on Jeep website

Selling price of the Jeep, P = $25,495

The down payment Molly has = $2,500

The Cash Allowance = $500

Number of months of payment, n = 84 months

The Annual Percentage Rate, APR, r = 1.9%

First Part:

Loan needed = $25,495 - $2,500 - $500 = $22,495

The amount of loan Molly needs = $22,495

Second Part:

The monthly payment is given by the formula;

$\displaystyle M = \mathbf{\dfrac{P \cdot \left(\dfrac{r}{12} \right) \cdot \left(1+\dfrac{r}{12} \right)^n }{\left(1+\dfrac{r}{12} \right)^n - 1}}$

Therefore;

$\displaystyle M = \dfrac{22,495 \times \left(\dfrac{0.019}{12} \right) \times \left(1+\dfrac{0.019}{12} \right)^{84} }{\left(1+\dfrac{0.019}{12} \right)^{84} - 1} \approx \mathbf{286.2}$

Molly's monthly payment will be M ≈ $286.2

Third part:

The total interest, I = Sum of payment - Loan amount

∴ The total interest, I ≈ $286.2/month × 84 month - $22,495 ≈ $1,545.8

The total interest Molly will pay using the loan, I ≈ $1,545.8

Fourth part:

The cost of the car, C, using the 1.9% APR financing plan is the sum of the down payment plus sum of the loan repayment

Therefore;

C ≈ $2,500 + $286.2/month × 84 months = $26,540.8

The cost of the car using the 1.9% APR financing plan, C ≈ $26,540.8

The question parameters obtained from a similar question are;

Selling price of the car = $25,495

Financing = 1.9% APR for 84 months with a cash allowance of $500

Learn more about loan payment here:

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3 0

2 years ago

Plz help PLZ IF CORRECT I’LL GIVE BRAINLIEST

vlada-n [284]

Step-by-step explanation:

products of

$2 \frac{2}{3} \times 3\frac{3}{4} \\ = \frac{2 \times 3 + 2}{3} \times \frac{3 \times 4 + 3}{4} \\ = \frac{8}{3} \times \frac{15}{4} \\ = 10$

Hope it will help :)

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2 years ago

What is the correct order of the prefixes, from smallest value to largest value? centi- kilo- micro- milli- deca-

never [62]

Answer:

micro-, milli-, centi-, deca-, kilo-

Step-by-step explanation:

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3 years ago