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Zinaida [17]
3 years ago
9

Claire is going to flip a coin 3 times. What is the probability of getting tails up on the first flip and heads up on both of th

e last 2 flips
Mathematics
1 answer:
kykrilka [37]3 years ago
7 0

Answer:

1/8

Step-by-step explanation:

A coin has two sides, 1 called heads, the other called tails.

The first coin flip Claire wants a tails. She has a 1/2 chance of getting tails.

The second coin flip Claire wants heads. She has a 1/2 chance of getting heads.

The third coin flip Claire wants heads. She has a 1/2 chance of getting heads.

Now, multiply the fractions together:

1/2 x 1/2 x 1/2 = 1/(2 x 2 x 2) = 1/8

1/8 is the probability of getting that order.

~

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Figure B is a scaled copy of Figure A.
musickatia [10]

<em>Greetings from Brasil...</em>

Comparing the distances AB and A'B ', we notice that AB = 3 and A'B' '= 9.

We can say that:

AB · X = A'B'

3 · X = 9

3X = 9

X = 9 ÷ 3

X = 3

Thus, figure B is 3x larger than figure A

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3 years ago
The two pentagons in the sketch below are congruent. Which sequence could transform pentagon GHIJK to pentagon
Oduvanchick [21]

Answer:

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4 0
3 years ago
Solve for x. 9x = 3x − 36
rusak2 [61]

Answer: x=-6

Step-by-step explanation:

In order to solve for "x", we must remember the following properties:

  • The Subtraction property of Equality states that:

        If a=b, then a-c=b-c

  • The Division property of Equality states that:

         If a=b, then \frac{a}{c}=\frac{b}{c}

Therefore, knowing these properties, we can solve for "x" to find its value.

First, we need to subtract 3x from both sides of the equation. Then:

9x-(3x) = 3x - 36-(3x)\\\\6x=-36

And finally, we can divide both sides of the equation by 6. Then we get:

\frac{6x}{6}=\frac{-36}{6}\\\\x=-6

3 0
4 years ago
Read 2 more answers
HELP PLEASE
Maurinko [17]
\bf \cfrac{x^2-x-42}{x-6}\implies \cfrac{(x+7)\underline{(x-6)}}{\underline{x-6}}\implies x+7

so.. the left-hand-side does indeed simplify to x+7, so the equation does check out.

however, notice something, for the equation of x+7, when x = 6, we get (6) + 7 which is 13.

BUT for the rational, we get    \bf \cfrac{x^2-x-42}{x-6}\qquad \boxed{x=6}\implies \cfrac{x^2-x-42}{\boxed{6}-6}\implies \stackrel{und efined}{\cfrac{x^2-x-42}{0}}

so, even though the siimplification is correct, the rational or original expression is constrained in its domain.
6 0
4 years ago
Help me please! If you DO decide to help, please explain it to me since I'm extremely confused! THANK YOU!
den301095 [7]

\bf \cfrac{(-4x^2)(2x^{-2}y)^3}{(16x^5)(4y^3)^2}\implies \cfrac{(-4x^2)(2^3x^{-2\cdot 3}y^3)}{(16x^5)(4^2y^{3\cdot 2})}\implies \cfrac{(-4x^2)(8x^{-6}y^3)}{(16x^5)(16y^6)} \\\\\\ \cfrac{-32x^{2-6}y^3}{256x^5y^6}\implies -\cfrac{x^{-4} y^3}{8x^5y^6}\implies -\cfrac{1}{8x^5x^{4}y^6y^{-3}}\implies -\cfrac{1}{8x^{5+4}y^{6-3}} \\\\\\ -\cfrac{1}{8x^9y^3}

8 0
3 years ago
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