In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.
For finding side a, you can answer this easily by the Law of Cosines. The equation is
a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9
Then, we use the Law of Sines to find angles B and C. The formula would be
a/sinA = b/sinB = c/sinC
9/sin54° = 11/sinB
B = 80.4°
9/sin54° = 8/sinC
C = 45.6°
The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
Answer:
See explaination for the details of the answer
Step-by-step explanation:
Defect per opportunity DPO = defects/ no. of opportunities = 2/25 = 0.08
Defect per million opportunities
DPMO = DPO * 1 million
DPMO = 0.08 * 1 million = 80,000
six sigma = 2.9, take the dpmo at higher level if not exact 80800 for 2.9
Answer: 8/9
Step-by-step explanation:
8/9 cannot be simplified. It's already in simplest form. if you want to turn it into decimal the answer will be .8 (bar notation above 8)
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