Answer:
20 gallons were used from the tank with the octane rating of 80.
Step-by-step explanation:
Given : One tank of gasoline has an octane rating of 140 and another tank of gasoline has an octane rating of 80. To obtain a mixture of 60 gallons with an octane rating of 120.
To find : How many gallons should be used from the tank with the octane rating of 80?
Solution : Let x be the volume of gas whose octane rating is 140 and
y be the volume of gas whose octane rating is 80.
Then, we form the equation as:
(1) 

or
.........[3]
(2) 
Now multiply equation (2) by 4
...........[4]
Subtract (4) from (3)



Put x in equation [4] we get,





Therefore, x=40 and y=20
So, 20 gallons were used from the tank with the octane rating of 80.
Answer:
E 240
Step-by-step explanation:
Geometric Distribution mean = (1- p) / p
16 = (1 - p) / p
16p = 1 - p ; 17p = 1 ; p = 1/17 = 0.058
Standard Deviation = (1 - p) / p^2
= (1 - 0.058) / (0.058)^2
0.942 / 0.003364
= 280 , closest to 240
Answer:
10
Step-by-step explanation:
6x = 60
Answer:
Solve for K by simplifying both sides of the inequality, then isolating the variable.
Inequality Form:
k > 1
<u>Interval Notation</u>:
(1, ∞)
Step-by-step explanation: