The answer is for this question is A
X^6 - 8, because it is (x^2)^3 - 2^3
Answer:
See explanations below
Step-by-step explanation:
Example of how to find the determinant of a 2×2 matrices is as shown;
![\left[\begin{array}{ccc}a&b\\c&d&\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%26%5Cend%7Barray%7D%5Cright%5D)
= (a*d)-(b*c)
= ad - bc
Applying this to solve the given questions
1) (3*4) - (-3*-1)
= 12 - (3)
= 9
2) (-12*5)-(-1*12)
= -60 - (-12)
= -60+12
= -48
3) (0*4)-(-1*17)
= 0-(-17)
= 0+17
= 17
4) (8*-1)-(-4*-1)
= -8-(4)
= -8-4
= -12
5) (2*-1)-(2*-1)
= -2-(-2)
= -2+2
= 0
6) 1(1) - 0(0)
= 1 - 0
= 1
Answer:
Step-by-step explanation:
hello :
the point-slope formula is :
y - y_1 = m(x - x_1) the point is A(x_1 , y_1 ) , m : the slope
in this exercice : x_1 = -1 y_1 = 4 m = 3
so : y - 4 = 3(x +1) ...an equation for this line .