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2 years ago

Describe a real world problem that you could solve using the volume of spheres

Mathematics

1 answer:

alexgriva [62]2 years ago

5 0

A toy company produces rubber balls that have a radius of 1.7 cm.

What is the volume of one rubber ball? Round to the

nearest hundredth of a centimeter.

20.58 cm3

If the price of the rubber needed to produce a ball is

$0.0045/cm3, what is the cost of producing one ball?

Round to the nearest cent.

If the company sells a ball for $0.50, how much profit

will it make on each ball?

$1.7 cm

20.58 cm^3, $0.09, $0.41

Hope this helps

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A line with a slope of

marishachu [46]

Answer:

(6-q)/(8-10)= -6

(6-q)/-2=-6

6-q=-12

-q=-18

q=18

8 0

3 years ago

An accounting professor is notorious for being stingy in giving out good letter grades. In a large section of 140 students in th

Arlecino [84]

Answer:

The 95% confidence interval for the proportion of students that obtain a letter grade of B or better from this professor is (0.2056, 0.3544). The interpretation is that we are 95% sure that the true proportion of students who obtain a letter grade of B or better from this professor is between 0.2056 and 0.3544.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

140 students, so $n = 140$

B or better are grades of A or B.

5% earn As, 23% earn Bs, so $p = 0.05 + 0.23 = 0.28$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.28 - 1.96\sqrt{\frac{0.28*0.72}{140}} = 0.2056$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.28 + 1.96\sqrt{\frac{0.28*0.72}{140}} = 0.3544$

7 0

3 years ago

a piece of lumber is 2 1/4 ft long is cut into 3 equal pieces .How long will each piece of cut wood be ?

yaroslaw [1]

Answer: Each piece would be 3/4 feet long

Step-by-step explanation:

If the piece of lumber is 2 1/4 ft long, and it is cut into 3 pieces then divide

2 1/4 by 3 to find out how long each piece of cut wood would be.

2 1/4 is the same as 9/4

$\frac{9}{4} / \frac{3}{1}$ = 9/12 which also simplifies to 3/4

6 0

3 years ago

Will give brainliest

luda_lava [24]

Answer:

P (A and B)=8/9

Events A and B are not dependent.

Step-by-step explanation:

Probability of A AND B means the the probability (favorable outcomes divided by total) of choosing someone who has/did BOTH A and B (not neither or only one of them). 16 did both, so the probability is 16/18 /2/2 = 8/9.

The events are independent (not dependent) because choosing A does not affect choosing B.

4 0

3 years ago

Read 2 more answers

suppose you have ab on a coordinate plane located at a(-3,-4) and b(5,-4). under a dilation centered at (9,0), ab becomes a'b' w

Galina-37 [17]

The distace between the center of dilation and point a is diven by:

$d=\sqrt{(9-(-3))^2+(0-(-4))^2} \\ \\ =\sqrt{(9+3)^2+(0+4)^2}=\sqrt{12^2+4^2} \\ \\ =\sqrt{144+16}=\sqrt{160}=\sqrt{16\times10}=4\sqrt{10}$

The distance between the center of dilation and point a' is given by:

$d=\sqrt{(9-6)^2+(0-(-1))^2} \\ \\ =\sqrt{3^2+(0+1)^2}=\sqrt{3^2+1^2} \\ \\ =\sqrt{9+1}=\sqrt{10}$

It can be seen that the distance from the center of dilation to the image is 1/4 times the distance from the centre of dilation to the preimage.

Therefore, the scale factor is 1/4.

7 0

4 years ago