For this case we have the following system of equations:
Equating both equations we have:
We must find the solutions, for this we factor. We look for two numbers that, when multiplied, result in 4 and when added, result in 5. These numbers are 4 and 1:
Then, the factorized equation is of the form:
Thus, the solutions are:
We look for solutions for the variable "y":
Thus, the system solutions are given by:
ANswer:
The third answer has a domain of 3,5,8
Answer: In-center of the triangle is point N.
Step-by-step explanation:
We are given a triangle △JKL.
In triangle △JKL, they drew perpendicular bisectors of each side of the triangle.
Also we are given angle bisectors of the each of angles in given triangle.
Note: Perpendicular bisector is a line that intersect a segment into two equal parts and also perpendicular to it.
<em>Also note that the in-center is the point forming the origin of a circle inscribed inside the triangle. It is constructed by taking the intersection of the angle bisectors of the three vertices of the triangle.</em>
<h3>We can see that angle bisectors are intersecting at a point N. </h3><h3>
Therefore, in-center of the triangle is point N.</h3>
