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melomori [17]
1 year ago
12

Please help with the question below

Mathematics
1 answer:
lora16 [44]1 year ago
4 0

Considering the unit circle, it is found that the sine is negative on the third and on the fourth quadrant.

<h3>What is the unit circle?</h3>

For an angle \theta the unit circle is a circle with radius 1 containing the following set of points: (\cos{\theta}, \sin{\theta}).

Hence, from the above explanation, the sine is negative when y is negativem, which is on the third and on the fourth quadrant.

More can be learned about the unit circle at brainly.com/question/16852127

#SPJ1

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In a right triangle, the measure of one acute angle is 12 more than twice the measure of the other acute angle. Find the measure
soldi70 [24.7K]

Given:

In a right triangle, the measure of one acute angle is 12 more than twice the measure of the other acute angle.

To find:

The measures of the 2 acute angles of the triangle.

Solution:

Let x be the measure of one acute angle. Then the measure of another acute is (2x+12).

According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees. So,

x+(2x+12)+90=180

3x+102=180

3x=180-102

3x=78

Divide both sides by 3.

x=\dfrac{78}{3}

x=26

The measure of one acute angle is 26 degrees. So, the measure of another acute angle is:

2x+12=2(26)+12

2x+12=52+12

2x+12=64

Therefore, the measures of two acute angles are 26° and 64° respectively.

8 0
3 years ago
Kayshaunna owes 4 people 6$. She mistakenly says she is in debt 30$. How many people would she owe 6$ to if her debt was 30$
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Answer:

The answer is 5 people

Step-by-step explanation:

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6 0
2 years ago
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What is the simplified form of StartRoot StartFraction 72 x Superscript 16 Baseline Over 50 x Superscript 36 Baseline EndFractio
aalyn [17]

Answer:

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Step-by-step explanation:

Apparently you want to simplify ...

  \sqrt{\dfrac{72x^{16}}{50x^{36}}}

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  1/a^b = a^-b

  (a^b)^c = a^(bc)

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So the expression simplifies as ...

  \sqrt{\dfrac{72x^{16}}{50x^{36}}}=\sqrt{\dfrac{36}{25x^{36-16}}}=\sqrt{\dfrac{36}{25x^{20}}}\\\\\sqrt{\left(\dfrac{6}{5x^{10}}\right)^2}=\boxed{\dfrac{6}{5x^{10}}}

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givi [52]

Answer: a = 1 b = 7

Step-by-step explanation:

x^2(y^3)^4/x.y^5 = x^a.y^b

x^2(y^12) = x^a.y^b

(x^2).(y^12)/x^y^5 = x.y^7

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Hope this helps :D

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