Please help with the question below
1 answer:
Considering the unit circle, it is found that the sine is negative on the third and on the fourth quadrant.
<h3>What is the unit circle?</h3>For an angle the unit circle is a circle with radius 1 containing the following set of points:
.
Hence, from the above explanation, the sine is negative when y is negativem, which is on the third and on the fourth quadrant.
More can be learned about the unit circle at brainly.com/question/16852127
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1) Taking in account that the function is f(x)= -(2/3) |x+4|-6, I enclose a file with the graph.
That helps you to conclude:
a) The graph of f(x) has a vertex on (-4, -6)
b) When you multiply a function times 2/3 it is vertically compressed which is equivalent to horizontally streched.
c) The graph of f(x) opens downward
d) The domain of f(x) is all the real values (the absolute function accepts any value of x either positive or negative)
Answer: the graph of f(x) is horizontally stretched.
That helps you to conclude:
a) The graph of f(x) has a vertex on (-4, -6)
b) When you multiply a function times 2/3 it is vertically compressed which is equivalent to horizontally streched.
c) The graph of f(x) opens downward
d) The domain of f(x) is all the real values (the absolute function accepts any value of x either positive or negative)
Answer: the graph of f(x) is horizontally stretched.