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2 years ago

Which set of population data is the least dispersed from its mean? 2, 3, 2, 9 4, 0, 4, 0 6, 2, 2, 2 9, 3, 5, 3.

Mathematics

1 answer:

exis [7]2 years ago

7 0

The set of data 6, 2, 2, 2 will have the least dispersion from its mean.

From four sets of data, we take the mean of 6,2,2,2

$\rm mean =\dfrac{ Sum \ of\ data}{Number \ of\ data}$

So the mean will be

$\rm mean =\dfrac{ 6+2+2+2}{4}=\dfrac{12}{4} =3$

So the mean of the data (6,2,2,2) is 3 which has the least dispersion from its every data as compared to the other data

Thus the set of data 6, 2, 2, 2 will have the least dispersion from their mean.

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4x+y=10 ( ?,-6) <br><br> Find the missing value. Show all work.

ivann1987 [24]

Answer:

(4 , -6) x = 4.

Step-by-step explanation:

Note that in a pair under ( X , Y) always consists of X as it's 1st element and Y as it's second element.

so now we know that ( ? , -6) has an X value which is unknown.

inorder to find X you'll simply need to use the Y value you're given which is Y = -6 from ( ? , -6)

now plot the y value into the equation

4X + Y = 10 , Y = -6

4X + (-6) = 10

4X + - 6 = 10 ...... we know that A + - B = A - B

4X - 6 = 10

now take -6 to the right side

when -6 is taken to the right side, it changes to +6

and so ..

4X = 10 + 6

4X = 16

now divide both sides by 4 to find X

4X / 4 = 16 / 4

4 the coefficient of X which is 4 cancels with out denominator which is now 4

X = 16 / 4

16 ÷ 4 = 4.

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2 years ago

Given f(x) and g(x) = f(x) + k, look at the graph below and determine the value of k.<br> k=______.

LenKa [72]

Answer:

Step-by-step explanation:

Look at one of the coordinates to find k. For this example I'll look at the y-intercepts (0, 3) (for g(x)) and (0, -2) (for f(x))

g(0) = 3

g(0) = f(0) + k

3 = -2 + k

5 = k

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2 years ago

How many segments of length x will fit into the circumference of this circle? Express your answer to the nearest hundredth.

Trava [24]

Answer:

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2 years ago

Help please I’ll make it brainliest!!!!!

mr Goodwill [35]

Step-by-step explanation:

it is very simple, once you remember that "kilo" means 1000, "mili" means 1/1000, and "centi" means 1/100.

and therefore 1 cg = 10 mg, or 1 cm = 10 mm.

"deci" means 1/10.

and therefore 1 dm = 100 mm, 1dg = 100 mg.

9.32 kg = 9.32×1000 = 9320 g

1.429 g = 1.429/1000 = 0.001429 kg

287 g = 287/1000 = 0.287 kg

4.6 L = 4.6×1000 = 4600 mL

0.119 L = 0.119×1000 = 119 mL

9936 mL = 9936/1000 = 9.936 L

26793 mL = 26793/1000 = 26.793 L

0.06 L = 0.06×1000 = 60 mL

170 cg = 170×10 = 1700 mg

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2674 cm = 2674/100 = 26.74 m

11.

9.05 mm = 9.05/100 = 0.0905 dm

12.

2 L = 2×1000 = 2000 mL

13.

62.4 L = 62.4×1000 = 62400 mL

14.

99.9 mm = 99.9/1000 = 0.0999 m

15.

4.34 g = 4.34×100 = 434 cg

16.

10 km = 10×1000 m = 10×1000×1000 = 10000000 mm

17.

65 cL = 65/100 = 0.65 L

18.

105 mL = 105/1000 = 0.105 L

19.

0.27 g = 0.27×100 = 27 cg

20.

7777 m = 7777/1000 = 7.777 km

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2 years ago

Dave is comparing the circumferences of several trees in his yard. The oak tree is 0.539 meters in circumference, the ash tree h

stepan [7]

Answer: c. elm

Step-by-step explanation:

Given : The circumference of the oak tree= 0.539 meters

= $0.539\times100=53.9\text{ cm}$ [∵ 1 m = 100 cm] (1)

The circumference of the ash tree= 0.509 yards

$=0.509\times3\text{ feet}$ [∵ 1 yard = 3 feet]

$=0.509\times3\times 30.48\text{ cm}$ [∵ 1 foot = 30.48 cm]

$=46.54296\approx46.54\text{ cm}$ (2)

The circumference of the elm tree = 6281.70 millimeters

$=\dfrac{6281.70}{10}=628.17\text{ cm}$ (3)

The circumference of the poplar tree = 0.000385 miles

$=0.000385 \times5280\text{ feet}$ [∵ 1 mile = 5280 feet]

$=0.000385 \times5280\times30.48\text{ feet}$ [∵ 1 foot = 30.48 cm]

$=61.959744\approx61.96\ \text{ cm}$ (4)

From (1) , (2) , (3 ) and (4) it is clear that

46.54< 53.9 < 61.96 < 628.17

Hence, the elm tree has the greatest circumference.

5 0

3 years ago