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qwelly [4]
3 years ago
13

A salesperson earns $8 per hour plus 6% commission on her sales. In a week when she worked 40 hours, her total earnings were $69

2.
What was the total amount of her sales for the week?
Mathematics
1 answer:
mash [69]3 years ago
5 0

Answer:

372

Step-by-step explanation:

8x40=320

692-320=372

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2. A soccer field is bordered on three sides by a parking lot of width x. The total
notsponge [240]

Answer: 50m

Step-by-step explanation:

this is the logical way I solved it:

1. Find the area of the entire area thing

300*200=60000

2. Subtract the area of the field from the area of the entire place

60000-30000=30000

3. Divide the area of the parking by three because there are three sides

30000 ÷ 3 = 10000

4. Divide 10000 by 200, not 300 because we want to find the side with one <em>x</em>, not two <em>x</em> (there are two sides adding on to the side with 300, but only one side on the side with 200)

10000÷200= 50

I know the steps are weird, but I know this is the right answer because this was on the unit test (same misspelling and everything lol) and during tutoring my teacher showed me how to do it, but of course I had to forget the steps.

4 0
3 years ago
Need help idk how to slove this
Gemiola [76]

Hi!

I'm not sure how to slove this, but I do know how to solve it ;D

<h3>We can't know the exact value of y, but we can isolate y on one side. First, multiply by z on both sides. </h3>

\frac{x+y}{z*z}=3*z

x + y = 3 * z

<h3>Now subtract x from both sides.</h3>

x - x + y = 3 * z - x

<u>y = 3 * z - x</u>

<h2>The answer is y = 3 * z - x</h2>

Hope this helps! :)

-Peredhel

8 0
3 years ago
Read 2 more answers
Make a conjecture about the sum of primes based on the following pattern:
Setler [38]
14= 7+7
16= 8+8
18= 9+9
20= 9+11
22= 10+12
24= 12+12
26= 7+8+11
6 0
3 years ago
A right triangle has a height of 20 cm and a base of 10 cm. What is the area of the triangle? (A = 1/2 bh)
alisha [4.7K]

Answer:

100 because its way too ez

7 0
3 years ago
Read 2 more answers
If sin(theta) =4/5 and is in quadrant 2, the value of cot(theta
iren [92.7K]
\sin\theta= \frac{4}{5} &#10;\\&#10;\\\sin^2\theta+\cos^2\theta=1&#10;\\ \cos\theta=\pm \sqrt{1-\sin^2\theta} =\pm \sqrt{1-( \frac{4}{5})^2 } =\pm \sqrt{1- \frac{16}{25} } =\pm \sqrt{\frac{9}{25} }=\pm \frac{3}{5}}

\theta \in II \Rightarrow \cos\theta\ \textless \ 0 \Rightarrow \cos\theta=-\frac{3}{5}

\cot\theta= \frac{\cos\theta}{\sin\theta}= \frac{-\frac{3}{5}}{\frac{4}{5}}  =- \frac{3}{4}

5 0
3 years ago
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