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Goshia [24]
1 year ago
10

I need help with this please

Mathematics
2 answers:
Sati [7]1 year ago
7 0

Answer:it is c

Step-by-step explanation:

the earnings per hour is 8, therefore to get the total earnings you will do 8*the nuber of hours to get the earnings

as easy as that

Delicious77 [7]1 year ago
3 0

Answer:

I'm pretty sure its C.

Step-by-step explanation:

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What is an equation of the line that passes through the points (4,-2) and (-1,3)
Paraphin [41]

Answer:

<h3>The slope is -1.</h3>

Step-by-step explanation:

To find an equation of the line that passes through the points, you have to use the slope formula.

Slope:

\Rightarrow \sf{\dfrac{y_2-y_1}{x_2-x_1} }

y2=3

y1=(-2)

x2=(-1)

x1=4

Solve.

3--2/-1-4=5/-5=-1

The slope is -1.

4 0
1 year ago
Read 2 more answers
Which two statements below are true ?
Marrrta [24]
A) 2/6 = 1/3
1/3 = 1/3

True 

------

b) 1/3 > 2/4
1/3 > 1/2 

False
------

c) 1/8 > 3/4

False
------

d) 2/5 < 1/2

True
------

e) 4/12 < 1/6

False
------

f) 3/5 = 7/10

False
------

This is all just a process of simplifying fractions down.

The only 'true' statements there are is option A and D.
6 0
3 years ago
Someone wanna heelpp!!!!!<br>​
Aleks04 [339]

Answer:

95

Step-by-step explanation: is the answer

3 0
3 years ago
Read 2 more answers
Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a
hram777 [196]

Answer:

(1,1)

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points (x_1,y_1)\,,\,(x_2,y_2) is equal to \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

So,

EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}

Perimeter of a figure is the length of its outline.

EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

Put (x,y)=(1,1)

\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9

This is true.

So, the point (1,1) satisfies the equation \sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

So, point H is (1,1).

7 0
3 years ago
Name the sets of numbers to which -5 belongs to
kipiarov [429]
It would belong to integers, rational, and real numbers.
5 0
3 years ago
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