Answer:
i. sin(C) = 
ii. tan(C) = 
iii. sin(B) = 
Step-by-step explanation:
Given a right angled triangle ABC, with a right angle at A.
<ABC = 
<BCA = 
AC = 9 = 1
CB = 18 = 2
Applying Pythagoras theorem to ΔABC, we have;
AB = 
= 
= 
Thus applying the trigonometric ratios, it would be observed that;
i. sin(C) = 
ii. tan(C) = 
iii. sin(B) = 
No it had to be 9 because AC is equal to 9 and the diagonals will both be the same length
Answer:
0
Step-by-step explanation:
duh
2 circles and a rectangle I'm guessing this is like the layout of a net