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2 years ago

A certificate of deposit with $600 principal earns 2. 5% interest for 6 years. How much is the interest earned for 6 years?

1 answer:

5 0

$~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$600\\ r=rate\to 2.5\%\to \frac{2.5}{100}\dotfill &0.025\\ t=years\dotfill &6 \end{cases} \\\\\\ I = (600)(0.025)(6)\implies I=90$

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“twice the sum of a number and 6 is more than 84”

stealth61 [152]

Answer:

Step-by-step explanation:

2x+6=84

2x=78

find your own way

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3 years ago

State the slope and y intercept of the graph of 9-x=2y

jasenka [17]

The equation of a line is given by y = mx + c; where m is the slope.
The given equation is 9 - x = 2y
y = -1/2 x + 9/2
Therefore, the slope is -1/2 and the y-intercept is 9/2.

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3 years ago

What is the volume of a rectangular prism with a length of 4 a width of 6 and a height of 2?

pentagon [3]

Answer: Volume = 48

Step-by-step explanation:

V = L * W * H

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V = 48

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3 years ago

Use the substitution method to solve the system of equations

Sergeeva-Olga [200]

Answer:

x=1/4

y = -2

(1/4, -2)

Step-by-step explanation:

4x -y =3

y =-8x

substitute y =-8x into the first equation. Everywhere you see y put 8x

4x -y =3

4x - (-8x) =3

4x+8x=3

combine like terms

12x = 3

divide by 12

12x/12x = 3 /12

x = 1/4

now we need to find y

y = -8x

y = -8 * 1/4

y = -2

8 0

3 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$