In Mr. Green's class, we can clearly see that there are 10 girls.
Hope this helps! :)
Answer:
The equation can define y as a function of x and it also can define x as a function of y.
Step-by-step explanation:
A relation is a function if and only if each value in the domain is mapped into only one value in the range.
So, if we have:
f(x₀) = A
and, for the same input x₀:
f(x₀) = B
Then this is not a function, because it is mapping the element x₀ into two different outputs.
Now we want to see it:
x + y = 27
defines y as a function of x.
if we isolate y, we get:
y = f(x) = 27 - x
Now, this is a linear equation, so for each value of x we will find an unique correspondent value of y, so yes, this is a function.
Now we also want to check if:
x + y = 27
defines x as a function of y.
So now we need to isolate x to get:
x = f(y) = 27 - y
Again, this is a linear equation, there are no values of y such that f(y) has two different values. Then this is a function.
Answer:
Tim has the smaller y-intercept = 2780
Step-by-step explanation:
Tim explains that Marshas saving increases by 225 per month. After 8 months, Marsha's has 4580 in his account.
Let m be the gradient(change per month)
Let y be the initial money in Marsha's account.
Let y1 be the amount in Marsha's account after 8 months
y1 = 4580
Let x be the initial month d money was put into the account.
Let x1 be the number of months it takes for money to increase to 4580
x1= 8
(y - y1) /(x - x1) = m
(y - 4580)/ (x - 8) = 225
y - 4580 = 225(x - 8)
y - 4580 = 225x - 1800
y = 225x - 1800 + 4580
y = 225x + 2780
Comparing with y = mx + c, c(intercept) = 2780
For Paul,
y - 1400 = 56(x + 26)
y -1400 = 56x + 1456
y = 56x + 1456 + 1400
y = 56x + 2856
Comparing with y = mx + c, c(intercept) = 2850
Therefore comparing Tim's Y intercept and Paul's Y intercept,
2780 < 2856
Tim's function smaller y intercept = 2780
The midpoint of these two numbers is 0.035
1, 2, 4, 7, 14, 28
You can look at it as
1 x 28 = 28
2 x 14 = 28
4 x 7 = 28
hope this helps :)
