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Feliz [49]
3 years ago
11

Line e passes through points (9, 9) and (1, 4). Line f passes through points (1, 5) and (9, 10). Are line e and line f parallel

or perpendicular?
Mathematics
1 answer:
astraxan [27]3 years ago
8 0

Answer:

Let A(9, 9) & B(1, 4) are two point through which Line e passes.

Equation of e is given by

y - y1 = y2 - y1/ x2 - x1(x - x1)

or, y - 9 = 4-9/1-9 (x - 9)

or, -8y + 72 = -5x + 45

or, 5x - 8y + 27 = 0...........1.

Again,

consider C (1, 5) & D (9, 10) are other two points through with Line f pass through.

Also, eqn of f is,

y- 5 = 10-5/9-1 (x - 1)

or, 8y - 5 = 5x - 5

or, 5x - 8y =0 ...........2.

Let m1 and m2 are slopes between the lines.

Now, slope of 1. = - coef. of x/ coef. of y

= -5/-8 = 5/8 =m1

& slope of 2. = -5/-8 = 5/8 = m2

Since slopes of lines i. e. m1 = m2, so the lines are parallel to each other.

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san4es73 [151]

its good to know if a number is positive or negative because something as simple as forgetting the signs such as - + could drastically change your answer

6 0
3 years ago
11 less than three times a number is the same as 75 less than the product of -1 and the number. Find the value of the number.​
larisa [96]

Answer: x = -16

Step-by-step explanation:

3x - 11 = -x - 75 then solve. see photo attached for work.

3 0
3 years ago
In official NHL hockey puck is shaped like a cylinder with a diameter of 3 inches and a volume of 7.1 in.³. What is the height o
Natali [406]

Answer:

1 inch

Step-by-step explanation:

The formula for the volume of a cylinder:

V = πr²h, where r=radius and h = height

Using 7.1 for 'V' and 1.5 for 'r' (1/2 of the diameter), we can fill in the values and solve for 'h':

7.1 = π(1.5)²h or 7.1 = 7.065h

h = 1 inch

6 0
4 years ago
Prove by only manipulating one sin(^4)x-cos (^4)x=2sin (^2)x-1
larisa86 [58]
Factor a difference of squares:

\sin^4x-\cos^4x=(\sin^2x-\cos^2x)(\sin^2x+\cos^2x)

This reduces to

\sin^2x-\cos^2x

due to the Pythagorean identity. By the same identity, you have

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and you're done.
3 0
3 years ago
Trig question ———————
Stels [109]

Answer:

1) \cos(A)  = 0.948(appx)

2) \sin(A)  = 0.316(appx)

3) \tan(A)  = 0.333(appx)

Step-by-step explanation:

Using Pythagorean theorem ,

Hypotenuse =

\sqrt{ {6}^{2} +  {2}^{2}  }  =  \sqrt{36 + 4}  =  \sqrt{40}  = 2 \sqrt{10}

We know that

  • \sin( \alpha )  =  \frac{side \: opposite \: to \:  \alpha }{hypotenuse \: of \: triangle}
  • \cos( \alpha )  =  \frac{side \: adjacent \: to \:  \alpha }{hypotenuse \: of \: triangle}
  • \tan( \alpha )  =  \frac{side \: opposite \: to \:  \alpha }{side \: adjacent \: to \:  \alpha }

Where \ alpha is an angle of tge triangle.

In the triangle given above , \ alpha = angle \: A . So,

1) \cos(A) = \frac{6}{2 \sqrt{10} }  =   \frac{3}{ \sqrt{10} }  = 0.948(appx)

2) \sin(A) = \frac{2}{2 \sqrt{10} }  =   \frac{1}{ \sqrt{10} }  = 0.316(appx)

3) \tan(A) = \frac{2}{6}  =  \frac{1}{3}  = 0.333(appx)

8 0
3 years ago
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