Question

If you drop a rock from a great height, about how fast will it be falling after 5 seconds, neglecting air resistance?.

Answer 1

Answer:

v = 49.05 m/s^2

Explanation:

Let's use the uniform acceleration equation to find our final velocity.

$v = u + at$

v = final velocity

u = initial velocity

a = gravitational acceleration

t = time taken

Assuming the rock is at rest initially, u becomes zero.

$v = 0 + 9.81(5)$

$v = 49.05 m/s^2$