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anastassius [24]
3 years ago
9

Two bar magnets are placed side by side so that the north pole of one magnet is next to the south pole of the other magnet. If t

hese magnets are then pushed toward a coil of wire, would you expect an emf to be induced in the coil? Explain your answer.
(REAL ANSWERS PLEASE! I ALWAYS GET PEOPLE STEALING MY POINTS FOR THE HECK OF IT! IT'S A WASTE OF YOUR TIME! I will just report you if you do.)
Physics
1 answer:
Anika [276]3 years ago
4 0
The induced voltage is proportional to the time derivative of the net magnetic flux density. This is called faradays law of magnetic induction. Because you have a north and a south pole right next to each other (assuming they are magnets of equal strength) the total net magnetic flux will be zero. This is because the north end of one magnet adds a positive flux while the south end of the other magnet contributes negative flux.
As a result, the induced EMF will be zero. (I'm almost done with my PhD in electromagnetics engineering, so you can take this answer to the bank :) )
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Formula One racers speed up much more quickly than normal passenger vehicles, and they also can stop in a much shorter distance.
Afina-wow [57]

Answer

given,

initial speed of the car = 90 m/s

final speed of the car = 0 m/s

distance taken to stop = 110 m

calculating the acceleration of the car = ?

using the equation of motion

v² - u² = 2 a s

0² - 90² = 2 x a x 100

a = \dfrac{-90^2}{2\times 100}

   a = 40.5 m/s²

acceleration of the formula one car is equal to a = 40.5 m/s²

7 0
4 years ago
Isn’t it funny how the people who delete my questions are the ones with my brainliests? P.S Free Points! Your Welcome!
Nuetrik [128]

Answer:

yessss, hilarious.

Explanation:

thank you, btw

6 0
3 years ago
Read 2 more answers
The oxygen molecule, O2, has a total mass of 5.30×10-26 kg and a rotational inertia of 1.94×10-46 kg-m2 about an axis perpendicu
Nady [450]

Answer:

\omega=2.85*10^{13}\frac{rad}{s}

Explanation:

The translational kinetic energy depends on the mass and speed of the body, as follows:

K_T=\frac{mv^2}{2}\\K_T=\frac{5.30*10^{-26}kg(1.49*10^3\frac{m}{s})^2}{2}\\\\K_T=1.18*10^{-19}J

While rotational kinetic energy depends on the moment of inertia and the angular velocity of the body, as follows:

K_R=\frac{I\omega^2}{2}(1). We know that:

K_R=\frac{2}{3}K_T(2)

Replacing (1) in (2):

\frac{I\omega^2}{2}=\frac{2}{3}K_T\\\\\omega=\sqrt{\frac{4}{3}\frac{K_T}{I}}\\\omega=\sqrt{\frac{4}{3}\frac{1.18*10^{-19}J}{1.94*10^{-46}kg\cdot m^2}}\\\omega=2.85*10^{13}\frac{rad}{s}

4 0
4 years ago
What is the displacement for a person that walks 3.0km north and 8.0 km south
Oduvanchick [21]

Answer:

5 km

Explanation:

x = |3 - 8| = 5 km

6 0
4 years ago
A 0.015 kg marble moving to the right at 0.225 m/s makes an elastic head-on collision with a 0.030 kg shooter marble moving to t
bonufazy [111]

Answer:

0.09 m/s to the right

Explanation:

The principle of conservation of linear momentum states that in a system of colliding objects, the total momentum before collision is equal to the total momentum after collision, provided there is no external force.

The total momentum, in this question, is the sum of the momentum of the the two marbles. We assume velocity to the right is positive while to the left is negative. Thus, total initial momentum is

P_i = 0.015\times0.225+ 0.030 \times(-0.180) = 0.002025

After collision, the first marble goes left. Let the velocity of the other marble be v. Then we have

P_f = 0.015\times(-0.315) + 0.030v = 0.030v - 0.004725

Equating both momenta,

P_i = P_f

0.002025 = 0.030v - 0.004725

v = 0.09 \text{ m/s}

Hence, the larger goes right with a velocity of 0.09 m/s (since it has a positive sign).

4 0
3 years ago
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