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igomit [66]
3 years ago
9

Work out 5/8−2/5 Give your answer in its simplest form.

Mathematics
1 answer:
Inessa05 [86]3 years ago
7 0
\frac{5}{8} -  \frac{2}{5}

First, find the LCD (least common denominator) of the two fractions.
List the multiples of each denominator and find the one that is common.
Multiples of 8: 8, 16, 24, 32, 40
Multiples of 5: 5, 10, 15, 20, 25, 30, 35, 40
40 is your LCD.

Second, what can you divide by to make the denominators of each fraction '40'? Whatever you do to the bottom you must do to the top.
\frac{5*5}{8*5} - \frac{2*8}{5*8}

Third, multiply.
\frac{25}{40} - \frac{16}{40}

Fourth, since the denominators are the same now, we can combine them.
\frac{25-16}{40}

Fifth, subtract '25 - 16' to get 9.
\frac{9}{40}

Since \frac{9}{40} is already in the simplest form, it is your answer.

Answer as fraction: \frac{9}{40}
Answer as decimal: 0.225




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Answer:

1/5x+51=2x+42

Step-by-step explanation:

1/5 of x, the number, plus 51  is equal to 2 times the number plus 42.

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the perimeter of a rectangle is 55 inches. the ratio of the length to width is 7:4. use proportions to find the area of the rect
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Answer:

Step-by-step explanation:

let : x the length and y the width    .... ( x  > y and x ; y reals numbers )

the perimeter is : 2(x+y)

2(x+y) = 55...(1)

x/y = 7/4 ...(2)

by (2) : x = (7/4)y

subsct in (1) : 2( (7/4)y +y ) =55

(7/2)y +2y =55

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3 years ago
PLEASE HELP! WILL GIVE 70 POINTS!!
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Answer:

A=189\ mm^2

Step-by-step explanation:

<u>Surface Areas </u>

Is the sum of all the lateral areas of a given solid. We need to compute the total surface area of the given prism. It has 5 sides, two of them are equal (top and bottom areas) and the rest are rectangles.

Computing the top and bottom areas. They form a right triangle whose legs are 4.5 mm and 6 mm. The area of both triangles is

\displaystyle A_t=2*\frac{b.h}{2}=b.h=(4.5)(6)=27 mm^2

The front area is a rectangle of dimensions 7.7 mm and 9 mm, thus

A_f=b.h=(7.5)(9)=67.5 \ mm^2

The back left area is another rectangle of 4.5 mm by 9 mm

A_l=b.h=(4.5)(9)=40.5  \ mm^2

Finally, the back right area is a rectangle of 6 mm by 9 mm

A_r=b.h=(6)(9)=54 \ mm^2

Thus, the total surface area of the prism is

A=A_t+A_f+A_l+A_r=27+67.5+40.5+54=189\ mm^2

\boxed{A=189\ mm^2}

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A

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