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Llana [10]
2 years ago
14

Slove for X= what would this be for Mai poured 2.6 liters of water into a partially filled pitcher. The pitcher then contained 1

0.4 liters.
Which equation best represents the situation?


2.6\cdot⋅10.4 = x

, Not Selected

2.6 + 10.4 = x

, Not Selected

x + 2.6 = 10.4

, Not Selected
Incorrect answer:

x - 10.4 = 2.6

Results for item 16.
16
0 / 1 point
Solve for x in the equation you chose.

x =
Incorrect answer:
8.3
Mathematics
1 answer:
alexandr1967 [171]2 years ago
5 0

Answer:

  x + 2.6 = 10.4

  x = 7.8

Step-by-step explanation:

If 2.6 liters are added to x liters with the result that 10.4 liters then exist, the model is ...

  2.6 +x = 10.4 . . . . . . . 2.6 added to x gives 10.4

The commutative property of addition lets you rewrite this to ...

  x +2.6 = 10.4

__

Subtracting 2.6 from both sides of the equation gives its solution:

  x +2.6 -2.6 = 10.4 -2.6

  x = 7.8

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A recent study at UGA (March 5, 2008) suggests that students with cell phones may take more risks than students that do not have
Ira Lisetskai [31]

Answer:

(a) -2.8

b) (1) Reject H0: p = 0.50 in favor of HA: p < 0.50; there is sufficient evidence to conclude that less than half of all UGA female students who, if they had a cell phone, would be willing to walk somewhere after dark that they would normally not go.

Step-by-step explanation:

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

H0: p = 0.50

This means that:

\mu = 0.5, \sigma = \sqrt{0.5*0.5} = 0.5

In a random sample of 305 UGA female students, 128 responded that, if they had a cell phone, they would be willing to walk somewhere after dark that they would normally not go.

This means that n = 305, X = \frac{128}{305} = 0.4197

a) Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.4197 - 0.5}{\frac{0.5}{\sqrt{305}}}

z = -2.8

Pvalue:

We are testing the hypothesis that the proportion is less than 0.5, which means that the pvalue of the test is the pvalue of z = -2.81.

Looking at the z-table, z = -2.8 has a pvalue of 0.0026

(b) What is the correct conclusion for this hypothesis test at the 0.05 level of significance?

0.0026 < 0.05, which means that we reject the null hypothesis, that the proportion is 0.5, and accept the alternate hypothesis, that the proportion is less than 0.5, option (1).

6 0
3 years ago
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