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Llana [10]
1 year ago
14

Slove for X= what would this be for Mai poured 2.6 liters of water into a partially filled pitcher. The pitcher then contained 1

0.4 liters.
Which equation best represents the situation?


2.6\cdot⋅10.4 = x

, Not Selected

2.6 + 10.4 = x

, Not Selected

x + 2.6 = 10.4

, Not Selected
Incorrect answer:

x - 10.4 = 2.6

Results for item 16.
16
0 / 1 point
Solve for x in the equation you chose.

x =
Incorrect answer:
8.3
Mathematics
1 answer:
alexandr1967 [171]1 year ago
5 0

Answer:

  x + 2.6 = 10.4

  x = 7.8

Step-by-step explanation:

If 2.6 liters are added to x liters with the result that 10.4 liters then exist, the model is ...

  2.6 +x = 10.4 . . . . . . . 2.6 added to x gives 10.4

The commutative property of addition lets you rewrite this to ...

  x +2.6 = 10.4

__

Subtracting 2.6 from both sides of the equation gives its solution:

  x +2.6 -2.6 = 10.4 -2.6

  x = 7.8

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The quadratic equations and their solutions are;

9 ± √33 /4 = 2x² - 9x + 6.

4 ± √6 /2 = 2x² - 8x + 5.

9 ± √89 /4 = 2x² - 9x - 1.

4 ± √22 /2 = 2x² - 8x - 3.

Explanation:

Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.

We have to solve all of the five equations to be able to match the equations with their solutions.

2x² - 8x + 5, here a = 2, b = -8, c = 5.                                                  x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(5) / 2(2) = 8 ± √64 - 40/4.     24 can also be written as 4 × 6 and √4 = 2. So                                                                                     x = 8 ± 2√6 / 2×2= 4±√6/2.

2x² - 10x + 3, here a = 2, b = -10, c = 3.                                                   x =-b ± √b² - 4ac / 2a =-(-10) ± √(-10)² - 4(2)(3) / 2(4) = 10 ± √100 + 24/4. 124 can also be written as 4 × 31 and √4 = 2. So                                                                              x = 10 ± 2√31 / 2×2 = 5 ± √31 /2.

2x² - 8x - 3, here a = 2, b = -8, c = -3.                                                    x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4.     88 can also be written as 4 × 22 and √4 = 2. So                                                                             x = 8 ± 2√22 / 2×2 = 4± √22/2.

2x² - 9x - 1, here a = 2, b = -9, c = -1.                                                     x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4.                                          x = 9 ± √89 / 4.

2x² - 9x + 6, here a = 2, b = -9, c = 6.                                                    x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(6) / 2(2) = 9 ± √81 - 48/4.                                                                             x = 9 ± √33 / 4

To match we solve the monomials.

1. -15u^3 + 5u^3

Adding

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2.  10u^3 +(-5u^3)

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3. 10u^3 + 5u^3

Adding

10u^3 + 5u^3=15u^3

4.  5u^3+ (-10u^3)

Adding

5u^3-10u^3 =-5u^3

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