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aalyn [17]
2 years ago
13

Helppppp pleaseeee c: for brainliest

Mathematics
1 answer:
Alina [70]2 years ago
4 0

Answer:

I have no idea how to answer this... :P

<3

Sorry, I am quite a dummy.

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dentify the property used in this equation: 3 + [7 + (–4)] = (3 + 7) + (– 4) Evaluate the expression above.
Leno4ka [110]

Answer:

associative property with respect to addition and subtraction

3+[7+(-4)]=(3+7)+(-4)

3+[7-4]=10+(-4)

3+3=10-4

6=6

Step-by-step explanation:

i hope it will help you

7 0
3 years ago
What two numbers multiplies to 36 and add to negative 21
anastassius [24]
Factor 36 and add them, make sure both are negatie
1+36=37, nope
2+18=20 nope
3+12=15,nope
4+9=13, nope
6+6=12, nope

the closest one is 20

I hope you meant adds to -20, because if you did, then answer is -2 and -18

if you did mean 36 and adds to -21, then the numbers are \frac{-21-3 \sqrt{33} }{2} and \frac{-21+3 \sqrt{33} }{2}, aprox -19.1168 and  -1.8831
6 0
3 years ago
-3x &gt; 15 or 2x -1 &gt; 7<br> NEED HELP ASAP !!!
Artyom0805 [142]

Answer:

no.

Step-by-step explanation:

never.

5 0
3 years ago
Sophia has an ear infection. The doctor prescribes a course of antibiotics. Sophia is told to take 500 mg doses of the antibioti
ser-zykov [4K]

Answer:

Step-by-step explanation:

Part 1:

Let 

     Q₁ = Amount of the drug in the body after the first dose.

     Q₂ =  250 mg

As we know that after 12 hours about 4% of the drug is still present in the body.

For Q₂,

we get:

            Q₂ = 4% of Q₁ + 250

                  = (0.04 × 250) + 250

                  = 10 + 250

                  = 260 mg

Therefore, after the second dose, 260 mg of the drug is present in the body.

Now, for Q₃ :

We get;

          Q₃ = 4% of Q2 + 250

               = 0.04 × 260 + 250

               = 10.4 + 250

               = 260.4

For Q₄,

We get;

          Q₄ = 4% of Q₃ + 250 

                = 0.04 × 260.4 + 250

                = 10.416 + 250 

                = 260.416

Part 2:

To find out how large that amount is, we have to find Q₄₀.

Using the similar pattern

for Q₄₀,

We get;

           Q₄₀ = 250 + 250 × (0.04)¹ + 250 × (0.04)² + 250 × (0.04)³⁹

Taking 250 as common;

           Q₄₀ = 250 (1 + 0.04 + 0.042 + ⋯ + 0.0439)

                 = 2501 − 0.04401 − 0.04

           Q₄₀ = 260.4167

Hence, The greatest amount of antibiotics in Susan’s body is 260.4167 mg.

Part 3:

From the previous 2 components of the matter, we all know that the best quantity of the antibiotic in Susan's body is regarding 260.4167 mg and it'll occur right once she has taken the last dose. However, we have a tendency to see that already once the fourth dose she had 260.416 mg of the drug in her system, that is simply insignificantly smaller. thus we will say that beginning on the second day of treatment, double every day there'll be regarding 260.416 mg of the antibiotic in her body. Over the course of the subsequent twelve hours {the quantity|the quantity|the number} of the drug can decrease to 4% of the most amount, that is 10.4166 mg. Then the cycle can repeat.

3 0
3 years ago
How do you do 4x^2+3x-10=0
Likurg_2 [28]
4x^2+3x-10=0\\&#10;4x^2+8x-5x-10=0\\&#10;4x(x+2)-5(x+2)=0\\&#10;(4x-5)(x+2)=0\\&#10;x=\dfrac{5}{4} \vee x=-2&#10;
8 0
4 years ago
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