Is criminal justice an option?
Answer: Delayed acceleration technique
Explanation:
Answer:
It can help to have experts
Explanation:
I got the question correct
The only reaction that will most likely take place based on the activity series is; C: Ba + Na₂CO₃
<h3>Activity Series</h3>
From the activity series given, we can say that during a displacement reaction, the more reactive metal will always displace the lesser reactive metal from a compound.
Let us look at each of the given options;
A) Ag + FeCl₃
From the activity series, Silver(Ag) is less reactive than Iron(Fe) and as such Silver cannot displace iron from its' compound.
B) Zn + CaO
Zinc (Zn) is a less reactive metal than Calcium (Ca), so it cannot cannot displace Calcium from its' compound.
C) Ba + Na₂CO₃
Barium (Ba) is a more reactive metal than Sodium (Na), and therefore Barium will displace sodium from its compound in a displacement reaction.
D) Cr + KNO₃
Chromium (Cr) is a lesser reactive metal than Potassium (K), and it therefore cannot displace Potassium from its compound.
Complete question is;
Which reaction will most likely take place based on the activity series? Li > K Ba > CaNa > Mn > Zn > Cr> Fe> Cd Ni > H > Sb > Cu > Ag > Pd > Hg > Pt
A. Ag + FeCl₃
B. Zn + CaO
C. Ba + Na₂CO₃
D. Cr + KNO₃
Read more about Activity Series at; brainly.com/question/17469010
Answer:
The final speed of bicycle would be <u>27 m/s</u>².
Step-by-step explanation:
<u>Given</u> :
Initial velocity (u) = 15 m/s
Acceleration (a) = 3.0 m/s²
Time = 4 seconds
<u>To</u><u> </u><u>Find</u> :
Final velocity (v)
<u>Using</u><u> </u><u>Formula</u> :
![\longrightarrow{\pmb{\sf{v = u + at}}}](https://tex.z-dn.net/?f=%5Clongrightarrow%7B%5Cpmb%7B%5Csf%7Bv%20%3D%20u%20%2B%20at%7D%7D%7D)
v = final velocity
u = initial velocity
a = acceleration
t = time taken
<u>Solution</u> :
Substituting the values in the formula to find the final velocity :
![\longrightarrow{\sf{v = u + at}}](https://tex.z-dn.net/?f=%5Clongrightarrow%7B%5Csf%7Bv%20%3D%20u%20%2B%20at%7D%7D)
![\longrightarrow{\sf{v = 15 + (3.0 \times 4)}}](https://tex.z-dn.net/?f=%5Clongrightarrow%7B%5Csf%7Bv%20%3D%2015%20%2B%20%283.0%20%5Ctimes%204%29%7D%7D)
![\longrightarrow{\sf{v = 15 + (3 \times 4)}}](https://tex.z-dn.net/?f=%5Clongrightarrow%7B%5Csf%7Bv%20%3D%2015%20%2B%20%283%20%5Ctimes%204%29%7D%7D)
![\longrightarrow{\sf{v = 15 +(12)}}](https://tex.z-dn.net/?f=%5Clongrightarrow%7B%5Csf%7Bv%20%3D%2015%20%2B%2812%29%7D%7D)
![\longrightarrow{\sf{v = 15 +12}}](https://tex.z-dn.net/?f=%5Clongrightarrow%7B%5Csf%7Bv%20%3D%2015%20%2B12%7D%7D)
![\longrightarrow{\sf{v = 27 \: {m/s}^{2}}}](https://tex.z-dn.net/?f=%5Clongrightarrow%7B%5Csf%7Bv%20%3D%2027%20%5C%3A%20%20%7Bm%2Fs%7D%5E%7B2%7D%7D%7D)
![\star{\underline{\boxed{\red{\sf{v = 27 \: {m/s}^{2}}}}}}](https://tex.z-dn.net/?f=%5Cstar%7B%5Cunderline%7B%5Cboxed%7B%5Cred%7B%5Csf%7Bv%20%3D%2027%20%5C%3A%20%20%7Bm%2Fs%7D%5E%7B2%7D%7D%7D%7D%7D%7D)
Hence, the final speed of bicycle would be 27 m/s².
![\rule{300}{1.5}](https://tex.z-dn.net/?f=%5Crule%7B300%7D%7B1.5%7D)