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kompoz [17]
3 years ago
10

A college basketball player makes 80% of his free throws. At the end of a game, his team is losing by two points. He is fouled a

ttempting a three-point shot and is awarded three free throws. Assuming free throw attempts are independent, what is the probability that he makes at least two of the free throws?
Mathematics
2 answers:
Nitella [24]3 years ago
3 0
<span>.. P(at least 2 of 3 baskets) 
= P(2 of 3 baskets) + P(3 of 3 baskets) 
= (basket)(basket)(no basket) + (basket)(no basket)(basket) + (no basket)(basket)(basket) + (basket)(basket)(basket) 
= (0.8)(0.8)(0.2) + (0.8)(0.2)(0.8) + (0.2)(0.8)(0.8) + (0.8)(0.8)(0.8) 
= 3(0.8)(0.8)(0.2) + 0.8^3 
= 0.384 + 0.512 
= 0.896 

QED.</span><span>
</span>
weqwewe [10]3 years ago
3 0

Answer:

0.64

Step-by-step explanation:

He makes two from three throws, so he makes three throws or two throws.

We add the probabilities:

0.2*0.8^2+0.8^3

then this is equal to 0.64.

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a ball is shot straight upward. with it's height, in feet, after t seconds given by the function f(t)=-16t^2+192t. Find the aver
jekas [21]

ANSWER

80  {ms}^{ - 1}

EXPLANATION

The average velocity of the ball is the rateof displacement over the total time.

The height of the ball, in feet, after t seconds is given by the function:

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At time t=1, the height of the ball is

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f(1)=-16+192 = 176ft

At time t=6, the height of the ball is

f(6)=-16(6)^2+192(6)

f(6)=-16(36)+192(6)

f(6)=-576+1152 = 576

The average velocity

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=  \frac{576- 176}{6 - 1}

=  \frac{400}{5}

= 80  {ms}^{ - 1}

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