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lozanna [386]
2 years ago
9

PLLLLSSSSSSSSSSSSS HURRRRYYYYYYYYYYY

Mathematics
2 answers:
skad [1K]2 years ago
5 0

Answer: C. 3.078

Step-by-step explanation:

ANTONII [103]2 years ago
4 0

Answer:

The Answer would be "B"

Step-by-step explanation:

14.1005 - 11.023 = 3.0775

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5-7 write as an addition problem by adding the oppisite __+__.
Snezhnost [94]
Do you mean 5+7?
If so, that equals 12!
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The quantity q varies inversely with the square of m and directly with the product of r and x. When q is 2.5, mis 4 and the
saveliy_v [14]

Answer:

The constant of proportionality is 5.

Step-by-step explanation:

If the quantity q varies inversely with the square of m and directly with the product of r and x, then the variation equation is

q=k\frac{rx}{m^2}

When q=2.5, m= 4 and the

product of rx = 8.

We plug in this values to get;

2.5=k(\frac{8}{4^2})

2.5=k(\frac{8}{16})

2.5=\frac{1}{2}k

Multiply both sides by 2

k=2.5\times 2=5

The constant of proportionality is 5.

7 0
3 years ago
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Estimate the solution to the system of equations. asap, please!! I will mark for brain list
Darya [45]

Answer:

(1 \frac{1}{3}, 2 \frac{1}{3} )

Step-by-step explanation:

Given the 2 equations

7x - y = 7 → (1)

x + 2y = 6 → (2)

Multiplying (1) by 2 and adding to (2) will eliminate the y- term

14x - 2y = 14 → (3)

Add (2) and (3) term by term to eliminate y

15x = 20 ( divide both sides by 15 )

x = \frac{20}{15} = \frac{4}{3} = 1 \frac{1}{3}

Substitute this value of x into either of the 2 equations and solve for y

Substituting in (2)

\frac{4}{3} + 2y = 6

2y = 6 - \frac{4}{3} = \frac{14}{3} ( divide both sides by 2 )

y = \frac{7}{3} = 2 \frac{1}{3}

7 0
3 years ago
Pls answer fast IMPORTANT HURRY!!!! Why did the chicken cross the road
erma4kov [3.2K]

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Step-by-step explanation:

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5 0
3 years ago
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Consider a nuclear power plant that produces 1200 MW of power and has a conversion efficiency of 34 percent (that is, for each u
Pachacha [2.7K]

Answer:

Fuel used = 111,303,473,760 MJ/year

Step-by-step explanation:

Power production = Fuel energy * Efficiency

1200 MW = Fuel energy * 0.34

Fuel energy = 1200 MW / 0.34 =3529.41 MW

This means it consumes 3529.41 MJ/s.

Per year, it operates 365 days, 24 hours a day, 3600 seconds an hour.

To calculate the fuel used annualy we have to multiplicate by all these factors

Fuel used = 3529.41 MJ/s * 3600 s/hour * 24 hours/day * 365 days/year

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