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2 years ago

Please help im stuck!

Mathematics

1 answer:

Nutka1998 [239]2 years ago

4 0

Answer:

Step-by-step explanation:

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State if the two triangles are congruent. If they are, state how you know.

ankoles [38]

Answer:

Step-by-step explanation:

yes congruent, by AAS

the angles are stating , w/ the little red lines that they are the same.. so we know two angles of the triangles are the same, and we also know that one side touching is the same. so yes.. AAS.

6 0

2 years ago

Find the product.<br> (x2+6x +9)(x?) -<br> What’s the product

lesya692 [45]

Answer:

Step-by-step explanation:

(x² + 6x + 9)(x)= x²*x + 6x*x + 9*x = x³ + 6x² + 9x

4 0

2 years ago

Read 2 more answers

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

2 years ago

PLEASE HELP ME OUT...

e-lub [12.9K]

Answer:

y=-3

Step-by-step explanation:

there is no slope so x will not be used in the equation it also crosses at -3

3 0

3 years ago

Could someone please help me with this problem and possibly explain if you can? (Will give up brainiest answer if correct, if po

Andrej [43]

To find the answer you need to find the square root of e^2 to get e so what you do to one side of the equation you do to the other side of the equation so find the square root of 0.36.
e=positive or negative 0.6

3 0

3 years ago