1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pashok25 [27]
2 years ago
7

Help me with this geo question plss?!!

Mathematics
2 answers:
choli [55]2 years ago
7 0
We need to use sin cos and tan
We only have the opposite and adjacent so we can only use tan

tanX = opposite/ adjacent
TanX = 15/11
X = tan^-1(15/11 )
(inverse tan)

X=53.75°
denis-greek [22]2 years ago
6 0

Answer:

53.7

Step-by-step explanation:

You might be interested in
Write the raito as a fraction simplest from 12 boys and 15 girls​
kiruha [24]

Step-by-step explanation: We can write a ratio using the word "to", using a colon, or using a fraction bar.

Here, since we want our ratio in simplest form,

I would use a fraction bar.

Now, the problem asks us to compare

the number of boys to the number of girls.

We know that there are 12 boys

and we know that there are 15 girls.

So our ratio is 12/15.

However, this can be reduced to 4/5.

3 0
3 years ago
16 paise into rupees ​
denis-greek [22]

Answer:

0.16

Step-by-step explanation:

1paise = 1/100rupee

so, 16 paise = 16/100

16/100= 0.16

7 0
2 years ago
8. A right cone has a volume of 8,579 m3 and a radius of 16 m. Find its altitude.
Monica [59]

Answer:

Option A is correct.

Step-by-step explanation:

The formula used for finding the volume of right cone is:

Volume of Right cone = (1/3)π.r².h

We need to find altitude i.e h

Volume of cone=V = 8579 m^3

Radius=r = 16m

Altitude =h =?

Putting values,

8579 = (1/3) * 3.14 * (16)^2*h

8579 = 1/3 * 3.14 * 256 *h

8579 = 267.95 * h

=> h = 8579/267.95

h = 32.0 m

So, Altitude of right cone is 32.0 m

Option A is correct.

4 0
3 years ago
Evaluate the line integral for x^2yds where c is the top hal fo the circle x62 _y^2 = 9
natulia [17]
Parameterize C by

\mathbf r(t)=\langle x(t),y(t)\rangle=\langle3\cos t,3\sin t\rangle

where 0\le t\le\pi. Then the line integral is

\displaystyle\int_Cx^2y\,\mathrm dS=\int_{t=0}^{t=\pi}x(t)^2y(t)\left\|\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\right\|\,\mathrm dt
=\displaystyle\int_{t=0}^{t=\pi}(3\cos t)^2(3\sin t)\sqrt{(-3\sin t)^2+(3\cos t)^2}\,\mathrm dt
=\displaystyle3^4\int_{t=0}^{t=\pi}\cos^2t\sin t\,\mathrm dt

Take u=\cos t, then

=\displaystyle-3^4\int_{u=1}^{u=-1}u^2\,\mathrm du
=\displaystyle3^4\int_{u=-1}^{u=1}u^2\,\mathrm du
=\displaystyle2\times3^4\int_{u=0}^{u=1}u^2\,\mathrm du
=54
6 0
3 years ago
2(x+2) - 3(x-3)=x+7​
babunello [35]

Step-by-step explanation:

Let's solve your equation step-by-step.

2(x+2)−3(x−3)=x+7

Step 1: Simplify both sides of the equation.

2(x+2)−3(x−3)=x+7

(2)(x)+(2)(2)+(−3)(x)+(−3)(−3)=x+7(Distribute)

2x+4+−3x+9=x+7

(2x+−3x)+(4+9)=x+7(Combine Like Terms)

−x+13=x+7

−x+13=x+7

Step 2: Subtract x from both sides.

−x+13−x=x+7−x

−2x+13=7

Step 3: Subtract 13 from both sides.

−2x+13−13=7−13

−2x=−6

Step 4: Divide both sides by -2.

−2x

−2

=

−6

−2

x=3

Answer:

x=3

8 0
2 years ago
Other questions:
  • 1. Remember what we know about vertical angles and solve for x. (SHOW WORK)
    7·1 answer
  • Evaluate f(x)=-2x-5 for x=3
    8·1 answer
  • Tim dug a hole that was 16 1/2 inches deep.He left a pile of dirt next to the hole that was 8 3/4 inches high.Show how you could
    13·1 answer
  • Solve the equation.<br> 3y + 11 = -16
    12·2 answers
  • Giving 20 points please help
    9·2 answers
  • (6.6 x 10{-2}) (3.3 x 10{-4})
    6·1 answer
  • 4,183 divided by 47 for a quiz
    7·2 answers
  • The two points on the graph are given by the linear function f. a. Use the two points to find the equation that represents the l
    6·1 answer
  • Solve for b.<br><br> problem: a=3(B+C)<br><br> 1) B=A-C/3<br> 2) B=3A-C/3<br> 3) B=A-3C/3
    12·1 answer
  • Find the quotient: -10/9 divided by -5/7
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!