For this case we have a square whose sides are known and equal to 60 ft.
We want to find the diagonal of the square.
For this, we use the Pythagorean theorem.
We have then:
Answer:
from home to second base it is about:
m∠AOC = 108°
m∠AOC = 3m∠AOB
⇒m∠AOB = (m∠AOC) / 3 = 108 / 3 = 36°
Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
Answer:
n = 2
Step-by-step explanation:
2n - 8 = -2 (-3n + 12) + 8
2n - 8 = -(-6n + 24) + 8
2n - 8 = 6n - 24 + 8
2n - 8 = 6n - 16
-4n = -8
Divide each side by 4
n = 2
Answer:
Step-by-step explanation:
∠VTY is the tangent chord angle
- Tangent chord angle is the half of the intercepted arc
∠TSV is the inscribed angle.
- Inscribed angle is the half of the intercepted arc
<u>Since both of the mentioned angles refer to same arc, they are of same value.</u>
ΔTVS is isosceles as VS = ST, therefore the opposite angles are same.
<u>The measure of angle S</u>
<u>The required angle</u>
