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sattari [20]
2 years ago
13

Which equation has a solution of n = 4?

Mathematics
2 answers:
Klio2033 [76]2 years ago
5 0

Step-by-step explanation:

  1. 7n=28
  2. divide both side by 7
  3. n=28\7
  4. n=4
Allushta [10]2 years ago
4 0

Answer:

D. 7n = 28

Step-by-step explanation:

Let's substitute 4 for n in each equation to check if it the resulting equation is correct:

6+n=24\\ 6+4=24\\ 10\neq 24\rightarrow \text{Incorrect!}

5n=54\\5(4)=54\\20\neq54\rightarrow\text{Incorrect!}

12-n=16\\12-4=16\\8\neq16\rightarrow\text{Incorrect!}

7n=28\\7(4)=28\\28=28\rightarrow\text{Correct!}

Therefore the answer is D

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Dovator [93]

there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

<h3>How many 2-digit numbers are there in which the tens digit is larger than the ones digit?</h3>

A 2-digit number is written as:

a*10 + b

Where a and b are single-digit numbers.

Tens digit and ones digit refers to place values:

a is the tens digit, and b is the ones digit. The numbers with a larger tens digit than the ones digit are:

98, 97, 96, 95, 94, 93, 92, 91, 90, 87, 86, 85, 84, 83, 82, 81, 80, 76, 75, 75, 74, 73, 72, 71, 70, 65, 64, 63, 62, 61, 60, 54, 53, 52, 51, 50, 43, 42, 41, 40, 32, 31, 30, 21, 20, 10.

We can see that there are 46 numbers in that list, so we conclude that there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

If you want to learn more about place values:

brainly.com/question/12386995

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