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sattari [20]
2 years ago
13

Which equation has a solution of n = 4?

Mathematics
2 answers:
Klio2033 [76]2 years ago
5 0

Step-by-step explanation:

  1. 7n=28
  2. divide both side by 7
  3. n=28\7
  4. n=4
Allushta [10]2 years ago
4 0

Answer:

D. 7n = 28

Step-by-step explanation:

Let's substitute 4 for n in each equation to check if it the resulting equation is correct:

6+n=24\\ 6+4=24\\ 10\neq 24\rightarrow \text{Incorrect!}

5n=54\\5(4)=54\\20\neq54\rightarrow\text{Incorrect!}

12-n=16\\12-4=16\\8\neq16\rightarrow\text{Incorrect!}

7n=28\\7(4)=28\\28=28\rightarrow\text{Correct!}

Therefore the answer is D

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12=q+23 I need help Im not good with fractions
Afina-wow [57]

Answer:

12 = q + 23 \\ -  q = 23 - 12 \\ -  q =  11 \\  \frac{ - q}{ -1 }  =  \frac{11}{ - 1}  \\ q =  - 11

it is actually kinda easy u just need to think harder but I still hope it helps

4 0
3 years ago
Estimate the area under the curve f(x) = 16 - x^2 from x = 0 to x = 3 by using three inscribed (under the curve) rectangles. Ans
FrozenT [24]

Answer:

43

Step-by-step explanation:

Estimate the area under the curve f(x) = 16 - x^2 from x = 0 to x = 3 by using three inscribed (under the curve) rectangles

First we find out the width of the rectangle

Δx=b−a/n,  a= 0 and b= 3, n= 3

so Δx= 1

Divide the interval [0,3] into  3 sub intervals of width=1

[0,1]     [1,2]     [2,3]

Now we plug in end point and evaluate the function

We take left endpoints

f(x) = 16 - x^2

f(0) = 16 - 0^2=16

f(1) = 16 - 1^2= 15

f(2) = 16 - 2^2= 12

Now sum = Δx(f(0) + f(1)+f(2))

= 1 (16+15+12)= 43


3 0
3 years ago
A car traveling at 28 m/s starts to decelerate steadily. It comes to a complete stop in 7 seconds. What is its acceleration?
Alika [10]
The function that models the scenario is
v = init_v + acceleration * time

Plug the values into the equation,
0 = 28 + a * 7 => -28 = a * 7 => a = - 28/7 m/s.
5 0
3 years ago
Read 2 more answers
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earnstyle [38]
X+2 < 7
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Any value where x was less than 5 would be correct.
8 0
3 years ago
Help me with this question please?
UNO [17]
\bf 3^{n+2}-3^n=8\cdot 3^n\implies \boxed{3^n\cdot 3^2}-3^n=8\cdot 3^n&#10;\\\\\\&#10;\stackrel{common~factor}{3^n}(3^2-1)=8\cdot 3^n\implies 3^2-1=\cfrac{8\cdot \underline{3^n}}{\underline{3^n}}\implies 3^2-1=8&#10;\\\\\\&#10;9-1=8\implies 8=8
6 0
3 years ago
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