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Wittaler [7]
3 years ago
11

12=q+23 I need help Im not good with fractions

Mathematics
1 answer:
Afina-wow [57]3 years ago
4 0

Answer:

12 = q + 23 \\ -  q = 23 - 12 \\ -  q =  11 \\  \frac{ - q}{ -1 }  =  \frac{11}{ - 1}  \\ q =  - 11

it is actually kinda easy u just need to think harder but I still hope it helps

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Simplify to create an equivalent expression. 8−4(−x+5) Choose 1 answer: A 4x−12 B −4x−12 C 4x+13 D 4x+5
Kaylis [27]

Answer:

A (4x-12)

Step-by-step explanation:

Still think of PEMDAS: 8-4(-x=5)

a) Multiply -4(-x + 5)

* -4(-x) = 4x (remember a neg x neg = pos)

* -4(5) = - 20

b) Now it reads = 8 +4x - 20

c) put all like terms together

* 8 - 20 = -12

6 0
3 years ago
How to solve for axis of symmetry for y=(x+2)(x-4)
lianna [129]

Answer:

x = 1

Step-by-step explanation:

you can first find the two zeroes

that would be

x + 2 = 0

x - 4 = 0

x = {-2, 4}

then you average them

-2 + 4 = 2

2 / 2 = 1

the aos is 1

5 0
2 years ago
Read 2 more answers
What answer to 1+7v+9
Sveta_85 [38]

Hey There!

In order to simplify this expression, you would have to combine the like terms.

9+1 = 10

Nothing else could be done, therefore the answer would be.

7v + 10

Hope this helped!

8 0
3 years ago
Read 2 more answers
Find the distance between each pair of points
algol [13]

Answer

\sqrt{34}

Step-by-step explanation

You would use the pythagorean theorem for this problem. The point on the y-axis is 5 away from (0,0). The point on the x-axis is 3 away. You would square these, leading from

5+3 to

25+9=\sqrt{34}

Answer is \sqrt{34}.

7 0
3 years ago
Five cupcakes and two cookies cost $19.75. Two cupcakes and four cookies cost $ 17.50.
alina1380 [7]

Answer:

Step-by-step explanation:

Let x and y represent the cost of a cupcake and cookie respectively.

Given that;

Five cupcakes and two cookies cost  $19.75.

5x+2y=19.75 ---------- 1

Two cupcakes  and four cookies cost $17.50.

2x+4y=17.50 --------------2

Let's solve the simultaneous equation by elimination;

Multiply equation 1 by 2;

10x+4y=39.50-------3\\

Subtract equation 2 from equation 3;

10x-2x+4y-4y=39.50-8x=22

8x=22

divide both sides by 8

\frac{8x}{8} =\frac{22}{8} \\x=2.75

Since we have the value of x, let substitute into equation 1 to get y;

5x+2y=19.75\\5(2.75)+2y=19.75\\13.75+2y=19.75\\2y=19.75-13.75\\2y=6\\y=\frac{6}{2} \\y=3.00

therefore , the cost of cupcakes and cookies are;

cupcakes=  2.75\\cookies= 3.00

PLEASE MARK ME AS BRAINLIEST

6 0
3 years ago
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