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solniwko [45]
4 years ago
5

How do I find the sum of the numbers as the product of their GCF and another sum

Mathematics
1 answer:
dangina [55]4 years ago
8 0
Find the same number in the numbers you have and that is your answer
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Simplify the expression. 12x^-6 y^10 times 3x^7 y
Vlada [557]

We need to simplify the expression:

12x^{-6}y^{10} \times (3x^{7}y)

Now, we know that we can resolve the exponents of the variables with the like terms only and we can multiply the coefficients independently:

Now,  

12x^{-6}y^{10} \times 3x^{7}y=(12 \times 3)\times (x^{-6}\times x^{7})\times (y^{10}\times y)

On simplifying the above expression we get:

36\times x^{(-6+7)}\times y^{(10+1)}

=36 \times x^{1}\times y^{11}

=36 \times x \times y^{11}

=36xy^{11}

So the simplified form of the expression 12x^{-6}y^{10} \times 3x^{7}y=36xy^{11}.

7 0
3 years ago
Emily's family loves to work together in the garden. They have a slight preference for flowers, as 60%, percent of their plants
murzikaleks [220]

That is 40% * 50

= 0.4 * 50

= 20 vegetables

4 0
4 years ago
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Help Please! I will give brainliest!!
seropon [69]
The answer is 32.7 b so the answer is 105 over 10
6 0
3 years ago
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A square has the same area as a rectangle whose
amid [387]

Answer:

C) 32 * 2**1/2

Step-by-step explanation:

For rectangle P = L + W = 24 but L = 2W so

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W = 8 and L = 2W = 16

A = L * W = 16 * 8 = 128

SO for the square with the same area

A = L * L = 128

L**2 = 128

L = 8 * 2**1/2

P = 4L = 32 * 2**1/2

6 0
3 years ago
Determine if the conditional and its converse are true. If they are both true, select which biconditional correctly represents t
Ugo [173]
The conditional,  <span>If four points are non-coplanar, then they are non-collinear, </span>is true:

This is, coplanarity is a necessary condition to be collinear.

The converse, <span>If four points are non-collinear, then they are non-coplanar, is false.

A counterexample that disproves this statement is the 4 vertices of a paralelogram, of course they are in a same plane and are not collinear.
</span> 


3 0
3 years ago
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