Answer: could you make the question a little clearer
Step-by-step explanation:
Answer:
The solution of the system of linear equations is 
Step-by-step explanation:
We have the system of linear equations:

Gauss-Jordan elimination method is the process of performing row operations to transform any matrix into reduced row-echelon form.
The first step is to transform the system of linear equations into the matrix form. A system of linear equations can be represented in matrix form (Ax=b) using a coefficient matrix (A), a variable matrix (x), and a constant matrix(b).
From the system of linear equations that we have, the coefficient matrix is
![\left[\begin{array}{ccc}2&3&-6\\1&-2&3\\3&1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%26-6%5C%5C1%26-2%263%5C%5C3%261%260%5Cend%7Barray%7D%5Cright%5D)
the variable matrix is
![\left[\begin{array}{c}x&y&z\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%26y%26z%5Cend%7Barray%7D%5Cright%5D)
and the constant matrix is
![\left[\begin{array}{c}12&-2&13\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D12%26-2%2613%5Cend%7Barray%7D%5Cright%5D)
We also need the augmented matrix, this matrix is the result of joining the columns of the coefficient matrix and the constant matrix divided by a vertical bar, so
![\left[\begin{array}{ccc|c}2&3&-6&12\\1&-2&3&-2\\3&1&0&13\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D2%263%26-6%2612%5C%5C1%26-2%263%26-2%5C%5C3%261%260%2613%5Cend%7Barray%7D%5Cright%5D)
To transform the augmented matrix to reduced row-echelon form we need to follow these row operations:
- multiply the 1st row by 1/2
![\left[\begin{array}{ccc|c}1&3/2&-3&6\\1&-2&3&-2\\3&1&0&13\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%263%2F2%26-3%266%5C%5C1%26-2%263%26-2%5C%5C3%261%260%2613%5Cend%7Barray%7D%5Cright%5D)
- add -1 times the 1st row to the 2nd row
![\left[\begin{array}{ccc|c}1&3/2&-3&6\\0&-7/2&6&-8\\3&1&0&13\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%263%2F2%26-3%266%5C%5C0%26-7%2F2%266%26-8%5C%5C3%261%260%2613%5Cend%7Barray%7D%5Cright%5D)
- add -3 times the 1st row to the 3rd row
![\left[\begin{array}{ccc|c}1&3/2&-3&6\\0&-7/2&6&-8\\0&-7/2&9&-5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%263%2F2%26-3%266%5C%5C0%26-7%2F2%266%26-8%5C%5C0%26-7%2F2%269%26-5%5Cend%7Barray%7D%5Cright%5D)
- multiply the 2nd row by -2/7
![\left[\begin{array}{ccc|c}1&3/2&-3&6\\0&1&-12/7&16/7\\0&-7/2&9&-5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%263%2F2%26-3%266%5C%5C0%261%26-12%2F7%2616%2F7%5C%5C0%26-7%2F2%269%26-5%5Cend%7Barray%7D%5Cright%5D)
- add 7/2 times the 2nd row to the 3rd row
![\left[\begin{array}{ccc|c}1&3/2&-3&6\\0&1&-12/7&16/7\\0&0&3&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%263%2F2%26-3%266%5C%5C0%261%26-12%2F7%2616%2F7%5C%5C0%260%263%263%5Cend%7Barray%7D%5Cright%5D)
- multiply the 3rd row by 1/3
![\left[\begin{array}{ccc|c}1&3/2&-3&6\\0&1&-12/7&16/7\\0&0&1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%263%2F2%26-3%266%5C%5C0%261%26-12%2F7%2616%2F7%5C%5C0%260%261%261%5Cend%7Barray%7D%5Cright%5D)
- add 12/7 times the 3rd row to the 2nd row
![\left[\begin{array}{ccc|c}1&3/2&-3&6\\0&1&0&4\\0&0&1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%263%2F2%26-3%266%5C%5C0%261%260%264%5C%5C0%260%261%261%5Cend%7Barray%7D%5Cright%5D)
- add 3 times the 3rd row to the 1st row
![\left[\begin{array}{ccc|c}1&3/2&0&9\\0&1&0&4\\0&0&1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%263%2F2%260%269%5C%5C0%261%260%264%5C%5C0%260%261%261%5Cend%7Barray%7D%5Cright%5D)
- add -3/2 times the 2nd row to the 1st row
![\left[\begin{array}{ccc|c}1&0&0&3\\0&1&0&4\\0&0&1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%260%260%263%5C%5C0%261%260%264%5C%5C0%260%261%261%5Cend%7Barray%7D%5Cright%5D)
From the reduced row echelon form we have that

Since every column in the coefficient part of the matrix has a leading entry that means our system has a unique solution.
<span>difference of squares formula:
</span>a^2<span> – b^</span>2<span> = (a + b)(a – b)
</span>so answers are
<span>(3 + xz)(–3 + xz)
</span><span>(y2 – xy)(y2 + xy)
</span><span>(64y2 + x2)(–x2 + 64y2)
</span><span>
cause
</span><span>(3 + xz)(–3 + xz)
= </span><span>(xz + 3 )(xz - 3)
= x^2z^2 - 9
--------------
</span>(y^2 – xy)(y^2 + xy)
= y^4 -x^2y^2
----------
<span>(64y^2 + x^2)(–x2 + 64y^2)
=</span>(64y^2 + x2)(64 - x^2)<span>
= 64^2 y^4 - x^4</span>
The Ostrich will take 64 minutes to cover 40 miles.
Data;
- rate = 25 miles in 40 minute
<h3>Rate</h3>
To calculate the time it will take the ostrich to cover 40 miles, we have to compare it with the rate (speed).

Cross multiply both sides

simplify the value

divide both sides by the coefficient of x

From the calculations above, it would take the ostrich 64 minutes to cover 40 miles.
Learn more on rates here;
brainly.com/question/8728504
Answer:
She needs 26 plastic bags.
Step-by-step explanation:
Given:
Amount of cups of snacks mix = 8 2/3
Rewriting 8 2/3 we get,
Amount of snacks mix = 
Number of Cups in each bag = 
She puts all the snacks mix in plastic bags
We need to find the number of plastic bags required to put all the snacks mix
Let number of plastic bag be x.
hence we can say that Number of Cups in each bag multiplied by number of plastic bag is equal to Amount of snacks mix.

Hence total number of plastic bags she needs is 26.