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Dafna11 [192]
2 years ago
15

Pls help i will give brainliest

Mathematics
1 answer:
Novosadov [1.4K]2 years ago
4 0
<h3>Answer:   -a > -b</h3>

Explanation:

Let's go over an example.

We'll have a = 1 and b = 7 which makes a < b true. Feel free to pick your own favorite pair of numbers such that b is larger than 'a'.

The corresponding opposites are:  -a = -1 and -b = -7

The relationship flips because the opposites of each number are flipped. So instead of saying -a < -b, we have -a > -b

Sure enough, -1 > -7 is a true statement. Use a number line to see this. I recommend a vertical number line.

In short, going from a < b to -a > -b means we flip the signs of each term, and we flip the inequality sign as well.

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Serga [27]

Answer:

-\frac{1}{5} t^{15}

Step-by-step explanation:

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3 0
3 years ago
What is the solution to the inequality 3a/2 &lt; 24
rusak2 [61]

Answer:

a < 16

Step-by-step explanation:

We must get a alone to solve this. So first multiply by 2

3a/2 < 24

*2

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8 0
2 years ago
To get on the top players list , don needs to have a minimum average score of 225 after playing four games. His scores on his fi
Black_prince [1.1K]
Average must be 225 or more
4 games so
\frac{score1+score2+score3+score4}{4}  \geq 225
score1=192
score2=214
score3=250
score4=?
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\frac{192+214+250+?}{4}  \geq 225
\frac{656+?}{4}  \geq 225
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8 0
3 years ago
Read 2 more answers
Kelly rides her bicycle from city a to city b how long is her ride ? A 70 miles B 24 miles
KATRIN_1 [288]
I think it is B (don't take me for certain cuz I don't know)
7 0
3 years ago
Read 2 more answers
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Sloan [31]

Answer:

Sum of \frac{7x}{x^2-4} and \frac{2}{x+2} is \mathbf{\frac{9x-4}{x^2-4}}

Option B is correct answer.

Step-by-step explanation:

We need to find sum of \frac{7x}{x^2-4} and \frac{2}{x+2}

Finding sum of  \frac{7}{x^2-4} and \frac{2}{x+2}:

\frac{7x}{x^2-4}+\frac{2}{x+2}

We know that x^2-4 =(x+2)(x-2)

Replacing x^2-4

\frac{7x}{(x+2)(x-2)}+\frac{2}{x+2}

Now, taking LCM of (x+2)(x-2) and (x+2) we get (x+2)(x-2)

=\frac{7x+2(x-2)}{(x+2)(x-2)}\\=\frac{7x+2x-4}{(x+2)(x-2)}\\=\frac{9x-4}{(x+2)(x-2)}\\=\frac{9x-4}{x^2-4}

So, Sum of \frac{7x}{x^2-4} and \frac{2}{x+2} is \mathbf{\frac{9x-4}{x^2-4}}

Option B is correct answer.

6 0
2 years ago
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