The answer is encryption
steganography would be hiding data, like in an image
digital forensics is the analysis done after an attack
and the last one is a security standard
The answer is d torque because
Answer:
Check the explanation
Explanation:
Keep two iterators, i (for nuts array) and j (for bolts array).
while(i < n and j < n) {
if nuts[i] == bolts[j] {
We have a case where sizes match, output/return
}
else if nuts[i] < bolts[j] {
what this means is that the size of nut is lesser than that of bolt and we should go to the next bigger nut, i.e., i+=1
}
else {
what this means is that the size of bolt is lesser than that of nut and we should go to the next bigger bolt, i.e., j+=1
}
}
Since we go to each index in both the array only once, the algorithm take O(n) time.
Answer:
- def ending_time(hour, minutes, seconds, work_time):
- if((seconds + work_time) // 60 > 0):
- minutes = minutes + (seconds + work_time) // 60
- seconds = (seconds + work_time) % 60
-
- if(minutes // 60 > 0):
- hour = hour + (minutes // 60)
- minutes = minutes % 60
- else:
- seconds = seconds + work_time
-
- return str(hour) + ":" + str(minutes) + ":" + str(seconds)
-
- print(ending_time(2,30,59, 12000))
Explanation:
The solution code is written in Python 3.
Firstly create a function ending_time that takes the four required input parameters.
Next, create an if statement to check if the numerator of (seconds + work_times) divided by 60 is over zero. If so, increment the minute and reassign the remainder of the seconds to the variable (Line 2-4).
Next, create another if statement again to check if the numerator of (current minutes) divided by 60 is over zero, if so increment the hour and reassign the remainder of the minutes to the variable (Line 6-8)
Otherwise, just simply add the work_time to the current seconds
At last return the time output string (Line 12).
What was the options they gave you?
