Answer:
True
Explanation:
It is TRUE that An Information System is the set of steps that need to be followed to ensure that software development proceeds in an orderly fashion.
This is evident in the fact that the Information system involves various stages and different elements such as data, people, procedures, hardware, and software.
All these elements form together to create several steps in software development in a suitable manner that meets the clients' and customers' needs.
Answer: Hello your question is poorly written attached below is the well written question
answer:
a) Determine ( compute ) the difference between the max and minimum value. determine the Min and max values using 1.5n comparisons
time efficiency = θ( n )
b) A(n-1) - A(0)
time efficiency = θ( 1 )
Explanation:
a) An unsorted array
To find the maximum and minimum values scan the array of elements , then determine ( compute ) the difference between the max and minimum value. to determine the range. Alternatively determine the Min and max values using 1.5n comparisons
Algorithm's time efficiency = θ( n )
b) A sorted array
To determine the range, we will determine the difference between the first and last element i.e. A(n-1) - A(0)
time efficiency = θ( 1 )
Answer: C
Explanation:
That way she can have slides for her advance class and leave out slides that her normal class doesn’t need
Answer:
Explanation:
The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int highest, lowest;
ArrayList<Integer> myArr = new ArrayList<>();
while (true) {
System.out.println("Enter a number [0-10] or -1 to exit");
int num = in.nextInt();
if (num != -1) {
if ((num >= 0) && (num <= 10)) {
count+= 1;
myArr.add(num);
} else {
System.out.println("Wrong Value");
}
} else {
break;
}
}
if (myArr.size() > 3) {
highest = myArr.get(0);
lowest = myArr.get(0);
for (int x: myArr) {
if (x > highest) {
highest = x;
}
if (x < lowest) {
lowest = x;
}
}
System.out.println("Number of Elements: " + count);
System.out.println("Highest: " + highest);
System.out.println("Lowest : " + lowest);
} else {
System.out.println("Number of Elements: " + count);
System.out.println("No Highest or Lowest Elements");
}
}
}