Describe two methods by which viruses can spread.
1 answer:
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Answer: Hello your question is poorly written attached below is the well written question
answer:
a) Determine ( compute ) the difference between the max and minimum value. determine the Min and max values using 1.5n comparisons
time efficiency = θ( n )
b) A(n-1) - A(0)
time efficiency = θ( 1 )
Explanation:
a) An unsorted array
To find the maximum and minimum values scan the array of elements , then determine ( compute ) the difference between the max and minimum value. to determine the range. Alternatively determine the Min and max values using 1.5n comparisons
Algorithm's time efficiency = θ( n )
b) A sorted array
To determine the range, we will determine the difference between the first and last element i.e. A(n-1) - A(0)
time efficiency = θ( 1 )
Answer:
Explanation:
The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int highest, lowest;
ArrayList<Integer> myArr = new ArrayList<>();
while (true) {
System.out.println("Enter a number [0-10] or -1 to exit");
int num = in.nextInt();
if (num != -1) {
if ((num >= 0) && (num <= 10)) {
count+= 1;
myArr.add(num);
} else {
System.out.println("Wrong Value");
}
} else {
break;
}
}
if (myArr.size() > 3) {
highest = myArr.get(0);
lowest = myArr.get(0);
for (int x: myArr) {
if (x > highest) {
highest = x;
}
if (x < lowest) {
lowest = x;
}
}
System.out.println("Number of Elements: " + count);
System.out.println("Highest: " + highest);
System.out.println("Lowest : " + lowest);
} else {
System.out.println("Number of Elements: " + count);
System.out.println("No Highest or Lowest Elements");
}
}
}
