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NemiM [27]
3 years ago
10

Which tool can effectively increase the curl of the subject’s lips?

Computers and Technology
2 answers:
kifflom [539]3 years ago
8 0
A. Blur tool is your answer
Lynna [10]3 years ago
4 0
I don’t know if you will get this right but

I think it can be A , or. D
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Bridge building is the business of: pure scientists, civil servants, or civil engineers?
LenKa [72]
Civil engineers is the correct business
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Bert started off his working life as a typesetter for a print house. With the advent of new technologies, Bert's job became redu
Inessa [10]

Answer:

Berth's job became redundant because she lacks the computing skills. Perhaps, she has been using manual or analog type writing machine to do her job and was doing it well but with the advent of computer that replaces analog type writer, she will become redundant.

Explanation:

She needs to learn how to use the computer to type and do her job efficiently in the print industry.

5 0
3 years ago
What is the difference between password protection and encryption? please answer quick, i cant pass this test for the life of me
sergiy2304 [10]

Answer:Password protection is like locking something in a safe-deposit. It means no one can get to the locked content without knowing the right combination. This method is used on separate documents, folders, and other data the computer's user may want to protect from other people who might have access to the device. The problem is, if someone interested in such content obtains the password or finds a way to open it without it, the content might be revealed despite the owner's efforts to keep it hidden. Unfortunately, there are a lot of ways hackers could obtain the password or hack in without it. For example, it could be obtained with the help of malware, or it might be guessed if the user chooses a weak password. Not to mention, when it comes to PDF documents, the passwords placed on them can be removed using the CMD window or specific.

Password encryption is a step up from password protection. The term can be a tad confusing because, in fact, you cannot encrypt the password itself. Instead, by setting up "password encryption" you are creating a password AND encrypting the contents of the file. In our example (see instructions below), the contents of the user's PDF document are not only password protected, but also encrypted. It is a process during which the content one wishes to keep secret is altered to make it unrecognizable. For example, if it is a text document, letters of each word might be shuffled with additional characters so the words would no longer make any sense. The reverse process is only available if the person who wants to decrypt this data can provide a specific decryption key or a password. In other words, even if the password is removed no one could read the hidden content as it still would need to be decrypted. Of course, it is important to realize you might be unable to retrieve it too if you lose the decryption key, aka, the password.



PLS MARK ME AS BRAINLIEST.

3 0
2 years ago
You are a visitor at a political convention with delegates; each delegate is a member of exactly one political party. It is impo
Fed [463]

Answer:

The algorithm is as follows:

Step 1: Start

Step 2: Parties = [All delegates in the party]

Step 3: Lent = Count(Parties)

Step 4: Individual = 0

Step 5: Index = 1

Step 6: For I in Lent:

Step 6.1: If Parties[Individual] == Parties[I]:

Step 6.1.1: Index = Index + 1

Step 6.2: Else:

Step 6.2.1 If Index == 0:

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

Step 7: Else

Step 7.1: Index = Index - 1

Step 8: Print(Party[Individual])

Step 9: Stop

Explanation:

The algorithm begins here

Step 1: Start

This gets the political parties as a list

Step 2: Parties = [All delegates in the party]

This counts the number of delegates i.e. the length of the list

Step 3: Lent = Count(Parties)

This initializes the first individual you come in contact with, to delegate 0 [list index begins from 0]

Step 4: Individual = 0

The next person on the list is set to index 1

Step 5: Index = 1

This begins an iteration

Step 6: For I in Lent:

If Parties[Individual] greets, shakes or smile to Party[i]

Step 6.1: If Parties[Individual] == Parties[I]:

Then they belong to the same party. Increment count by 1

Step 6.1.1: Index = Index + 1

If otherwise

Step 6.2: Else:

This checks if the first person is still in check

Step 6.2.1 If Index == 0:

If yes, the iteration is shifted up

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

If the first person is not being checked

Step 7: Else

The index is reduced by 1

Step 7.1: Index = Index - 1

This prints the highest occurrence party

Step 8: Print(Party[Individual])

This ends the algorithm

Step 9: Stop

The algorithm, implemented in Python is added as an attachment

<em>Because there is an iteration which performs repetitive operation, the algorithm running time is: O(n) </em>

Download txt
5 0
2 years ago
Please tell fast plzzzzzz.​
lana [24]

Answer:

True

Explanation:

4 0
2 years ago
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