Is it called a, "server".
Answer:
In Python:
def split(A):
L=[]; G=[]
for i in range(1,len(A)):
if (A[i] != A[0] and A[i] < A[0]):
L.append(A[i])
if (A[i] != A[0] and A[i] > A[0]):
G.append(A[i])
return L, G
Explanation:
This defines the function
def split(A):
This initializes the L and G lists
L=[]; G=[]
This iterates through the original list A
for i in range(1,len(A)):
This populates list L using the stated condition
<em> if (A[i] != A[0] and A[i] < A[0]):</em>
<em> L.append(A[i])</em>
This populates list G using the stated condition
<em> if (A[i] != A[0] and A[i] > A[0]):</em>
<em> G.append(A[i])</em>
This returns the two lists L and G
return L, G
The numbers of residues separate amino acids that are stabilized by hydrogen bonds in α helices is 3.6 amino acid residues.
<h3>Why are amino acids called residues?</h3>
The Amino acids are known to be compounds that are said to be called residues if there is two or more amino acids that are known to be bond with each other.
Note that the amino group on one amino acid is one that tends to interacts with the carboxyl group and as such form a peptide bond.
Therefore, The numbers of residues separate amino acids that are stabilized by hydrogen bonds in α helices is 3.6 amino acid residues.
Learn more about amino acids from
brainly.com/question/2526971
#SPJ1
Answer:
O(N!), O(2N), O(N2), O(N), O(logN)
Explanation:
N! grows faster than any exponential functions, leave alone polynomials and logarithm. so O( N! ) would be slowest.
2^N would be bigger than N². Any exponential functions are slower than polynomial. So O( 2^N ) is next slowest.
Rest of them should be easier.
N² is slower than N and N is slower than logN as you can check in a graphing calculator.
NOTE: It is just nitpick but big-Oh is not necessary about speed / running time ( many programmers treat it like that anyway ) but rather how the time taken for an algorithm increase as the size of the input increases. Subtle difference.
