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BartSMP [9]
3 years ago
12

A string that contains only 0s,1s, and 2s is called a ternary string. How many strings of 10 ternary digits (0, 1, or 2) are the

re that contain exactly two 0s, three 1s, and five 2s? Generalize this to the number of ternary strings of length k with a 0’s, b 1’s, and c 2’s where a + b + c = k.
Computers and Technology
2 answers:
alexdok [17]3 years ago
8 0

Answer:

Number of strings = (10, 2)×(8,3) = 2520

Explanation:

The number of possible combinations for taking two 0's is C(10, 2)

It remains 8 Positions

The number of possible combinations for taking three 1's is C(8,3)

So there remains 5 spots

malfutka [58]3 years ago
5 0

Answer:

2520

Explanation:

There are (10 2) ways to 0,'s whereas (8 3) ways to 1's and then location of then 2's are apply.

Like

10!/2!×3!×5!.

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Item = "quesadilla"
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Answer:

item = "quesadilla"

meat = "steak"

queso = False

guacamole = False

double_meat = False

base_price = 4.5

if item == "quesadilla":

base_price = 4.0

elif item == "burrito":

base_price = 5.0

if meat == "steak" or meat == "pork":

base_price += 0.50

if meat == "steak" and double_meat:

base_price += 1.50

elif meat == "pork" and double_meat:

base_price += 1.50

elif double_meat:

base_price += 1.0

if guacamole:

base_price += 1.0

if queso and item != "nachos":

base_price += 1.0

print(base_price)

Explanation:

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