What is the output of the following program?

Which skill type refers to the knowledge and ability to perform a task?

Thepotemich [5.8K]

Sound, Audio for engineering sound Quality's.

7 0

3 years ago

Write the definition of a class Phone containing: 1. A data member named model of type string. 2. A data member named partNumber

Nady [450]

Answer:

class Phone(object):

def __init__(self, model, partNumber, retailPrice):

self.model = model

self.part_number = partNumber

self.retail_price = retailPrice

def phone_specs(self):

print( "Phone model: {}\nPart number: {}\nRetail price: {}".format( self.model, self.part_number, self.retail_price))

phone1 = Phone("Nokia", "asd234", 200.0)

phone1.phone_specs()

Explanation:

A class is a blueprint of a data structure used to create objects of the same data types and methods. The Phone class is an object that creates an instance of the phone1 object. The phone_specs method is used to display the details of the phone1 object.

4 0

3 years ago

PLEASE HELPPPPPPP What should you always disconnect before installing hardware inside a computer’s case?

Ad libitum [116K]

Answer:

a) all cabling hope it helps

3 0

3 years ago

WordArt styles allow you to add ____.

maria [59]

As for this problem, the most probable and the most likely answer to this would be it depends on the person or the user of it since there aren't any options presented with the problem.

WordArt is there to be of use during presentations, during discussions, and other things. On the other hand, as the technological advancement takes leaps and bounds going forward, this utility seems to be underused and isn't expected to give a more impact to the reader or to the recipient of such document that contains it. This is typically used for people that aren't too familiar yet, as to how to utilize other programs to enhance their documents and files.

3 0

3 years ago

a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv

Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

#include <bits/stdc++.h>

using namespace std;

// chracter to digit mapping, and the inverse

// (if you want better performance: use array instead of unordered_map)

unordered_map<char, int> c2i;

unordered_map<int, char> i2c;

int ans = 0;

// limit: length of result

int limit = 0;

// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]

bool helper(vector<string>& words, string& result, int digit, int widx, int sum) {

if (digit == limit) {

ans += (sum == 0);

return sum == 0;

}

// if summation at digit position complete, validate it with result[digit].

if (widx == words.size()) {

if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {

if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result

return false;

c2i[result[digit]] = sum % 10;

i2c[sum%10] = result[digit];

bool tmp = helper(words, result, digit+1, 0, sum/10);

c2i.erase(result[digit]);

i2c.erase(sum%10);

ans += tmp;

return tmp;

} else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){

if (digit + 1 == limit && 0 == c2i[result[digit]]) {

return false;

}

return helper(words, result, digit+1, 0, sum/10);

} else {

return false;

}

// if word[widx] length less than digit, ignore and go to next word

if (digit >= words[widx].length()) {

return helper(words, result, digit, widx+1, sum);

}

// if word[widx][digit] already mapped to a value

if (c2i.count(words[widx][digit])) {

if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0)

return false;

return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);

}

// if word[widx][digit] not mapped to a value yet

for (int i = 0; i < 10; i++) {

if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;

if (i2c.count(i)) continue;

c2i[words[widx][digit]] = i;

i2c[i] = words[widx][digit];

bool tmp = helper(words, result, digit, widx+1, sum+i);

c2i.erase(words[widx][digit]);

i2c.erase(i);

}

return false;

}

void isSolvable(vector<string>& words, string result) {

limit = result.length();

for (auto &w: words)

if (w.length() > limit)

return;

for (auto&w:words)

reverse(w.begin(), w.end());

reverse(result.begin(), result.end());

int aa = helper(words, result, 0, 0, 0);

}

int main()

{

ans = 0;

vector<string> words={"GREEN" , "BLUE"} ;

string result = "BLACK";

isSolvable(words, result);

cout << ans << "\n";

return 0;

}

See more about C++ code at brainly.com/question/19705654

#SPJ1

3 0

2 years ago