Answer:
(x-9)^2
Step-by-step explanation:
Answer and explanation:
Farmer's number of apples = 96 apples
Given that Farmer needs to bag the apples so that there are at least 4 apples in each bag(not less than 4 apples in each bag) and not more than 10 apples in each bag
And also all apples in each bag are equal
We need to find the numbers between 4 and 10(including 4 and 10) that can divide 96 without a remainder
4 can divide 96= 24
5 cannot divide 96 without remainder
6 can divide 96 =16
7 cannot divide 96 without remainder
8 can divide 96=12
9 cannot divide 96 without remainder
10 cannot divide 96 without remainder
From the above we see that the factors of 96 = 4, 6, 8 between 4 and 10
4 apples = 24 bags
6 apples = 16 bags
8 apples = 12 bags
Therefore, there can be 3 possible ways of having equal number of apples in each bag between 4 and 10 apples
Here is the answer the app is called cymath btw
3a - 4b = 21
check (-2 , -3)
3(-2) -4(-3) =21
-6 +12 = 21
6 does not = 21 so NO
check (0 , 7)
3(0) -4(7) =21
0-28=21
-28 does not equal 21 so NO
check (-3 , -2)
3(-3) -4(-2) =21
-9 +8 = 21
1 does not = 21 so NO
check (7 , 0)
3(7) -4(0) =21
21 = 21
Choice D
