we have M is durectly porpotional to r^2
so M=(k)r^2
and when r=2, m=14
so 14=(k)(2)^2
k=14/4 =7/2
so when r=12
m= (7/2)(12)^2 =(7/2)(144) = 504
10u + t is the expressions shows the value of the reversal of digits in a two digit number, t = the tens digit and u = the ones digit. This can be obtained by multiplying 10 with the tens digit and adding unit digit.
<h3>Which is the required expressions?</h3>
Given that, in a two digit number,
t = the tens digit
u = the ones digit
The expression for the digit will be ,
10×t + u = 10t + u
The value of its reversal,
u = the tens digit
t = the ones digit
10×u + t = 10u + t is the required expression
For example,
37 = 10×3 + 7 = 30 + 7 and its reverse 73 = 10×7 + 3 = 70 + 3
Hence 10u + t is the expressions shows the value of the reversal of digits in a two digit number, t = the tens digit and u = the ones digit.
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The answer is 4 + 3i
It is the only one there with a 
or i
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The sequence is geometric, so
for some constant r. From this rule, it follows that
and we can determine the first term to be
Now, by substitution we have
and so on down to (D)
(notice how the exponent on r and the subscript on a add up to n)
Answer:
segment EH and segment E prime H prime both pass through the center of dilation.
Step-by-step explanation:
Center of dilation is point (0.1), same as H. Both, E(0,5) and H(0,1) are placed over y-axis, then E' and H' are also located at y-axis.
After dilation, H' is placed at (0,1) because it coincides with the center of dilation
Distance between E and center of dilation is 4 units, then E' should be at 4*3=12 units from the center of dilation and over y-axis. Therefore, E' is placed at (0, 13)
So, segment E'H' goes from (0,1) to (0,13), and pass through the center of dilation, like segment EH.
