A 2-column table with 9 rows. The first column is labeled year with entries 1970, 1975, 1980, 1985, 1990, 1995, 2000, 2005, 2010
1 answer:
The mean and median of the data(weight of trash in pounds for given years) given in the table is evaluated as:
- Mean ≈ 4.1 pounds
- Median = 4.44
Mean is the ratio of sum of the observations to the total number of observations.
Median is such a number for the arranged data set(ascending or descending order) such that to its left and to its right belong same number of observations.
For the given case, the data observations are:
3.25, 3.25, 3.66, 3.83, 4.57, 4.52, 4.74, 4.69, 4.44 (they are measurement of pounds of trash for specified years(in the problem statement) )
They are total 9 observations.
Their sum is 36.95 approx.
Thus, mean of this data set = sum/number of observations
Arranging the data in ascending order gives
3.25, 3.25, 3.66, 3.83, 4.44, 4.52, 4.57, 4.69, 4.74
There are 9 values, therefore, the fifth value would be median as to its left and to its right will lie four-four observations.
Thus, median of the data set = 4.44
Therefore, the mean and median of the data(weight of trash in pounds for given years) given in the table is evaluated as:
- Mean ≈ 4.1 pounds
- Median = 4.44
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