Answer: 45
=====================================================
Work Shown:
n = number of rolls = 150
p = probability of rolling a "1" = 0.3
n*p = expected number of "1"s that show up out of the 150 rolls
n*p = 150*0.3
n*p = 45
We expect about 45 ones will show up.
Using pythagorean theorem:
![\begin{gathered} c^2=a^2+b^2 \\ b=\sqrt[]{c^2-a^2} \\ b=\sqrt[]{19^2-17^2} \\ b=\sqrt[]{72} \\ b\approx8.5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20c%5E2%3Da%5E2%2Bb%5E2%20%5C%5C%20b%3D%5Csqrt%5B%5D%7Bc%5E2-a%5E2%7D%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B19%5E2-17%5E2%7D%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B72%7D%20%5C%5C%20b%5Capprox8.5%20%5Cend%7Bgathered%7D)
Step-by-step explanation:
7^3 × 7^(1÷2)
= 7^(3+ 0.5)
=7^3.5 ans
Answer:
b= (m)(-150)
Step-by-step explanation:
1800-1350 = 450
450/3 = 150
b= m*-150
