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galina1969 [7]
3 years ago
13

All books, except the reference books, are available for loan. How many books are available for loan?

Mathematics
1 answer:
Nana76 [90]3 years ago
4 0

Answer:

12106 :) hope this helps u

Step-by-step explanation:

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Shortest way to solve this question is to find the factors of the given expression.

The given expression is (x² + 13).

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4 years ago
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6 0
3 years ago
Got a calc 1 question,
belka [17]

v=\dfrac h{3x}\implies\dfrac{\mathrm dv}{\mathrm dt}=\dfrac{3x\frac{\mathrm dh}{\mathrm dt}-3h\frac{\mathrm dx}{\mathrm dt}}{3x^2}

By the chain rule,

\dfrac{\mathrm dh}{\mathrm dt}=\dfrac{\mathrm dh}{\mathrm dx}\dfrac{\mathrm dx}{\mathrm dt}

We have

h(x)=4e^{2x-6}-x^2+5\implies\dfrac{\mathrm dh}{\mathrm dx}=8e^{2x-6}-2x

and we're given that x changes at a constant rate of \frac{\mathrm dx}{\mathrm dt}=0.2 thousand people per minute, which means

\dfrac{\mathrm dv}{\mathrm dt}=\dfrac{3x\left(8e^{2x-6}-2x\right)\left(0.2\frac{\text{thousand people}}{\rm min}\right)-3h\left(0.2\frac{\text{thousand people}}{\rm min}\right)}{3x^2}

At the moment x=4 thousand people are in the park, we have h(4)=4e^2-11, so we find

\dfrac{\mathrm dv}{\mathrm dt}=\dfrac{12\left(8e^2-8\right)-3(4e^2-11)}{240}\dfrac{\text{thousand people}}{\rm min}=\dfrac{7(4e^2-3)}{80}\dfrac{\text{thousand people}}{\rm min}

or approximately 2.324 thousand people per minute.

5 0
4 years ago
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