All categories

2 years ago

Please help! Find the area of the figure.

Mathematics

1 answer:

Butoxors [25]2 years ago

3 0

To find the area, you must split the kite into many triangles.

(5*7*0.5)*2 + (4*5*0.5)*2 = 55

Answer: 55 square meters

You might be interested in

What is the area of the triangle?

Nutka1998 [239]

Answer:

742.5 in²

Step-by-step explanation:

area of triangle is 0.5 × base length × perpendicular height of the triangle

=0.5 × 33 × 45

=742.5 square inch

7 0

3 years ago

There are 22 paper clips in a draw 12 is gold an 10 are silver what fraction of the paper clip is gold?

yKpoI14uk [10]

Answer:

6/11

Step-by-step explanation:

there are 12 gold clips out of 22, so 12/22 and divide both sides by two to simplify.

7 0

3 years ago

Solve 2sin2(x) – 5sin(x) – 3 = 0. Let u = sin(x). Which of the following is equivalent to the given equation?

Orlov [11]

Answer:

$x=(-1)^{k+1}\cdot \dfrac{\pi}{6}+\pi k,\ k\in Z$

Step-by-step explanation:

Consider the equation

$2\sin^2x-5\sin x-3=0$

Substitute

$u=\sin x$

into the equation:

$2u^2-5u-3=0$

This is quadratic equation, where

$D=(-5)^2-4\cdot 2\cdot (-3)=25+24=49\\ \\\sqrt{D}=7$

Hence,

$u_1=\dfrac{-(-5)-\sqrt{D}}{2\cdot 2}=\dfrac{5-7}{4}=-\dfrac{1}{2}\\ \\u_2=\dfrac{-(-5)+\sqrt{D}}{2\cdot 2}=\dfrac{5+7}{4}=3$

Now, use the substitution again:

1. When $u_1=-\dfrac{1}{2},$ then

$\sin x=-\dfrac{1}{2}\\ \\x=(-1)^k\sin^{-1}\left(-\dfrac{1}{2}\right)+\pi k,\ k\in Z\\ \\x=(-1)^k\cdot \left(-\dfrac{\pi}{6}\right)+\pi k,\ k\in Z\\ \\x=(-1)^{k+1}\cdot \dfrac{\pi}{6}+\pi k,\ k\in Z$

2. When $u_2=3,$ then

$\sin x=3$

This equation has no solutions, because the range of $\sin x$ is $[-1,1]$ and 3>1.

4 0

4 years ago

Read 2 more answers

If dinah can skate 1/2 lap in 15 seconds,she can skate 1 lap in 7.5,30 seconds

disa [49]

If Dinah can skate 1/2 lap in 15 seconds,she can skate 1 lap in 30 seconds. This is because 15 multiplied by 2 is equal to 30.

7 0

3 years ago

Read 2 more answers

Which equation in point-slope form contains the point (2, 3) and has slope 2?

sergiy2304 [10]

------------------------------------------------------
Option A
------------------------------------------------------

------------------------------------------------------
Check if slope = 2
------------------------------------------------------
y + 2 = 2(x + 3)
y + 1 = 2x + 6
y = 2x + 6 - 1
y = 2x + 5

Slope = 2

Answer: Yes, Slope is 2

------------------------------------------------------
Check if it passed through (2, 3)
------------------------------------------------------
When x = 2
y = 2(2) + 5
y = 9

Answer: No, it does not passed through (2, 3)

------------------------------------------------------
Option B
------------------------------------------------------

------------------------------------------------------
Check if Slope is 2
------------------------------------------------------
y - 3 = 2(x - 2)
y - 3 = 2x - 4
y = 2x - 4 + 3
y = 2x - 1
Slope = 2

Ans : Yes, slope is 2.

------------------------------------------------------
Check if it passed through (2, 3)
------------------------------------------------------
when x = 2
y = 2(2) - 1
y = 4 - 1
y = 3

Answer : Yes, it passed through (2, 3)

------------------------------------------------------
Answer: (B) <span>y – 3 = 2(x – 2)
</span>------------------------------------------------------

6 0

3 years ago