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Setler79 [48]
4 years ago
11

What is the area of this trapezoid?

Mathematics
1 answer:
kramer4 years ago
6 0

Answer:

B)139.5

Step-by-step explanation:

Right-angled triangle formula A=ab/2 so find the area of both triangles left side: 2*9/2=9 right side 5*9/2= now find the area of the rectangle 9*12= add all them together 9+22.5+108=139.5

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What two number multiply to -48 and add to -2?
Novosadov [1.4K]

Answer:

6 and -8

Step-by-step explanation:

Solve:

xy = 48

x + y = -2

You can say y = -2-x = -(x+2) and then substitute that in the first:

-x(x+2) = 48

-x² -2x - 48 = 0

x² + 2x + 48 = 0

Quadratic formula can do the rest if you don't "see" the factorization.

5 0
4 years ago
Not sure how to solve this
Hoochie [10]

Answer:

  (x, y) = (0, -14), (2, -8), (3, -5)

Step-by-step explanation:

Put the given values into the equation and solve.

<u>x = 0</u>

  y = 3·0 -14 = -14

<u>y = -8</u>

  -8 = 3x -14

  6 = 3x . . . . . . add 14

  2 = x . . . . . . . divide by 3

<u>x = 3</u>

  y = 3·3 -14 = -5

__

The ordered pairs in your table are ...

  (x, y) = (0, -14), (2, -8), (3, -5)

_____

<em>Comment on the approach</em>

In this problem, you are only asked for one x-value for a given y-value. If there were more, you would solve the equation generically (x = (y+14)/3) and use that to compute the desired values of x.

3 0
4 years ago
Read 2 more answers
A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a
Vesnalui [34]

Answer:

2.5

Step-by-step explanation:

A triangle ABC with vertices A(0, 0), B(0, 4), and C(6, 0) is dilated to form a triangle A'B'C' with vertices A′(0, 0), B′(0, 10), and C′(15, 0). If the center of dilation is point A or A' (the origin), then

\dfrac{A'B'}{AB}=\dfrac{A'C'}{AC}.

Since

  • AB=4;
  • A'B'=10;
  • AC=6;
  • A'C'=15,

then the scale factor of the dilation is

k=\dfrac{10}{4}=\dfrac{15}{6}=2.5.

3 0
3 years ago
ABC has been translated 5 units to the right, as shown in the diagram. What is the length of ?
BARSIC [14]

Answer:

(A) 15 centimeters

Step-by-step explanation:

A midsegment of a triangle is always 2 things:

Half the size of the bottom of the triangle (in this case AC)

Parallel to the bottom of the triangle.

Since ABC is an equilateral triangle, we know that EVERY side is 30cm, including AC.

So the midsegment of ABC, LM, must be 15 cm.

Hope this helped!

6 0
3 years ago
What is the slope of the line that passes through the points (-8,-6) and (-18,6)
never [62]

the slope of the line is -6/5

8 0
3 years ago
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