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kirill [66]
4 years ago
14

Write an equation for a rational function with: vertical asymptotes at x = 2 and x = -5 x-intercepts (-1,0) and (1,0) horizontal

asymptote at y = 9
Mathematics
1 answer:
solong [7]4 years ago
7 0

Given vertical asymptotes x = 2 and x = -5 .

Therefore Factors of denominator (x-2)(x+5).

x-intercepts (-1,0) and (1,0) .

Therefore factors of (x+1)(x-1).

So far we got rational function = \frac{(x+1)(x-1)}{(x-2)(x+5)}.

Now, we are given horizontal asymptote at y = 9.

Multiplying above express by 9 on the top, we get

f(x)=\frac{9(x+1)(x-1)}{(x-2)(x+5)}.

<h3>Therefore, required rational function is f(x)=\frac{9(x+1)(x-1)}{(x-2)(x+5)}.</h3>
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