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3 years ago

11

Is −x+0+(−x)=0 a true statement?

1 answer:

dexar [7]3 years ago

6 0

Let's see it...

-x+0+(-x)=0 ???

There is a + before the parenthesis, the sign is the same.

-x+0-x = 0

Since the x have equal sign, we add them to get -2x

We have 2x - 0 = 0

Move the zero to the right, so 2x = 0

Divide both for 2...

x = 0

Substitute 0 to x, so -0+0+(-0) = 0

0 = 0 the statement is true

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Answer:

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Step-by-step explanation:

The standard form of an equation of a circle:

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(h, k) - center

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The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

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Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

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Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

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