Answer:
The answer to this question is given below in the explanation section.
Explanation:
The value stored by a variable can be changed after it is assigned(true).
The value of a variable can be changed after it is assigned, for example:
int a=10;
and we can change the value of variable a in letter program such as:
a=15;
Variables are a name for a spot in the computer's memory (true).
it is true, because the variables value stored in the computer's memory and we can access theses values by their name (variable name). so Variables are a name for a spot in the computer's memory.
Variable names can be words: such as temperature or height (true).
Yes, the variable name can be words such as height, width, temperature etc.
The value stored by a variable cannot be changed after it is assigned (false).
It is noted that the value stored by a variable can be changed after it is assigned. However, it is noted that is some programming language, you can't change the value of static variable.
Answer:
Theoretically one could design an architecture that would address 16 GB of memory with 32-bits of unique addresses.
Explanation:
Answer:
static int checkSymbol(char ch)
{
switch (ch)
{
case '+':
case '-':
return 1;
case '*':
case '/':
return 2;
case '^':
return 3;
}
return -1;
}
static String convertInfixToPostfix(String expression)
{
String calculation = new String("");
Stack<Character> operands = new Stack<>();
Stack<Character> operators = new Stack<>();
for (int i = 0; i<expression.length(); ++i)
{
char c = expression.charAt(i);
if (Character.isLetterOrDigit(c))
operands.push(c);
else if (c == '(')
operators.push(c);
else if (c == ')')
{
while (!operators.isEmpty() && operators.peek() != '(')
operands.push(operators.pop());
if (!operators.isEmpty() && operators.peek() != '(')
return NULL;
else
operators.pop();
}
else
{
while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))
operands.push(operators.pop());
operators.push(c);
}
}
while (!operators.isEmpty())
operands.push(operators.pop());
while (!operands.isEmpty())
calculation+=operands.pop();
calculation=calculation.reverse();
return calculation;
}
Explanation:
- Create the checkSymbol function to see what symbol is being passed to the stack.
- Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
- Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
- While the operators is not empty, keep pushing the character to the operators stack.
- At last reverse and return the calculation which has all the results.
Answer:
I have no clue. I wish I could help though.
Explanation:
Sorry
23 bits would leave room for 512 node numbers.
