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Oksana_A [137]
2 years ago
11

5. Simplify the expression and find its value when p= 4 and q = -5:

Mathematics
2 answers:
Ierofanga [76]2 years ago
7 0
  • <u>Answer</u>: -180

Step-by-step explanation:

\bf   \blue{ \boxed{  \bf p = 4 \:  \: and \:  \: q =  - 5 \Rightarrow pq = 4 \times ( - 5) =  - 20}}

3(p2q + pq2 - pq) - 6pq + 3pq2 =

3[-20 × 2 + (-20) × 2 - (-20)] - 6 × (-20) + 3 × 2 × (-20) =

3[-40 + (-40) + 20] - 6 × (-20) + 3 × 2 × (-20) =

3(-40 - 40 + 20) - 6 × (-20) + 3 × 2 × (-20) =

3(-80 + 20) - 6 × (-20) + 3 × 2 × (-20) =

3 × (-60) - 6 × (-20) + 3 × 2 × (-20) =

-180 + 120 + 6 × (-20) =

-180 + 120 + (-120) =

-180 + 120 - 120 =

-60 - 120 = -180

Andrei [34K]2 years ago
7 0

Answer:

-180

Step-by-step explanation:

3 ( p2q + Pq2 - pq ) - 6 pq +3pq2

3 [(4)(2)(-5) + (4)(-5)(2) - (4)(-5)] -6 (4)(-5) +3(4)(-5)(2)

3(-40-40+20) + 120 -120

3(-60) +0

-180+0

-180

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If f(1) = 7 and f(n) = 5f (n − 1) then find the value of f(5).
nevsk [136]

Answer:

f(5) = 4375

Step-by-step explanation:

Given f(n) = 5f(n - 1) and f(1) = 7

This allows us to find the next term in the sequence from the previous term

f(2) = 5f(1) = 5 × 7 = 35

f(3) = 5f(2) = 5 × 35 = 175

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66. Assuming after you substituted 3 in place of x, you followed order of operations, or PEMDAS.

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5 0
3 years ago
A researcher compares the effectiveness of two different instructional methods for teaching physiology. A sample of 178 students
xxTIMURxx [149]

Answer:

critical value = 1.645

The 90% confidence interval = ( -22.62, -17.58)

Step-by-step explanation:

Given that:

the sample  size n_1 = 178

the sample size n_2 = 226

the sample mean \overline x_1 = 54.4

the sample mean \overline x_2 = 74.5

population standard deviation \sigma_1 = 18.58

population standard deviation \sigma_2 = 9.52

level of significance ∝ = 1 - 0.90 = 0.10

The critical value for Z_{\alpha/2} = Z _{0.10/2} = Z_{0.005} is 1.645

For the construction of our confidence interval, we use 90% since that is used to find the critical value.

∴

The margin of error = Z \times\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}

1.645 \times\sqrt{\dfrac{18.58^2}{178} + \dfrac{9.52^2}{226}}

1.645 \times\sqrt{\dfrac{345.2164}{178} + \dfrac{90.6304}{226}}

1.645 \times\sqrt{2.34042}

\simeq 2.52

The lower limit = ( \overline x_1 - \overline x_2) - (M.O.E)

= ( 54.4-74.5) - (2.52)

= -20.1 - 2.52

= -22.62

The upper limit = ( \overline x_1 - \overline x_2) + (M.O.E)

= ( 54.4-74.5) + (2.52)

= -20.1 + 2.52

= -17.58

The 90% confidence interval = ( -22.62, -17.58)

6 0
3 years ago
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We can just divide 2x+14 by 2 to get the cost of one person, as the equation represents the total costs of two people.

So the equation is x+7, but it may be x+14 because you can’t split the pizza.

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