<u>Answer</u>-
<em>The total capacitive reactance of the circuit is </em><em>7.96 Ω.</em>
<u>Solution-</u>
Two capacitors, a 20 mF and a 30 mF, are connected in parallel to a 400 Hz source.
The effective/equivalent capacitance of the circuit is,
As, when capacitors are connected together in parallel, the equivalent capacitance in the circuit is equal to the sum of capacitance of all the individual capacitor.
We know that,
Where,
= Capacitive Reactance (in Ω)
f = frequency (in Hz)
C = Capacitance (in F)
Here given,
= ??
f = 400 Hz
C = 50 mF = 
F
Putting the values in the formula,
Therefore, the total capacitive reactance of the circuit is 7.96 Ω.
Find the values of x and y. a.x=90,y=47 b.x=43,y=47 c.x=47,y=43 d.x=90,y=43
Answer:
7 pales per horse
Step-by-step explanation:
35 ÷ 5 = 7
The average low temperature is -10.
-8+(-13)+(-4)+(-9)+(-16)= -50/5=-10
Answer:
0 ≤ u < 7 and 0 > u > - 7 and combining those two we get - 7 < u < 7.
Step-by-step explanation:
The given inequality is |u| - 2 < 5 ....... (1)
We have to solve this inequality.
Now, from the definition of f(x) = |x| we get, f(x) = x, when x ≥ 0 and
f(x) = -x when x < 0.
Hence, for u ≥ 0, the equation of inequality (1) becomes
u - 2 < 5
⇒ u < 7
Therefore, the solution is 0 ≤ u < 7 (Answer)
Again, for u < 0, the equation of inequality (1) becomes
- u - 2 < 5
⇒ u + 2 > - 5
⇒ u > - 7
Therefore, the solution becomes 0 > u > - 7 (Answer)
